A coin flipped 80 times . It lands tails 47 times . What is the P(heads)

A construction company is considering submitting bids for two contracts. It will cost the company \$10{,}000$10,000dollar sign,

baherus [9]

Answer:

0 dollars

=E(M)

=μ

M

=−$10,000(0.81)+$40,000(0.18)+$90,000(0.01)

=−8,100+7,200+900

=0

8 0

2 years ago

Read 2 more answers

A rectangular yard is fenced in using 319 feet of custom fence Your friends really like the fence and decide to fence in their y

Vsevolod [243]

We have been given that a rectangular yard is fenced in using 319 feet of custom fence Your friends really like the fence and decide to fence in their yard using the same fence. Their yard is similar but has a scale factor of 8/5 times the size of yours.

We are asked to find the length of fence that your friends should purchase.

Since the size of your friend's yard is $\frac{8}{5}$ times your yard, so your friend should purchase $\frac{8}{5}$ times the 319 feet.

$\text{Length of fence your friend should purchase}=\frac{8}{5}\times 319\text{ ft}$

$\text{Length of fence your friend should purchase}=8\times 63.8\text{ ft}$

$\text{Length of fence your friend should purchase}=510.4\text{ ft}$

Upon rounding our answer to nearest foot, we will get:

$\text{Length of fence your friend should purchase}\approx 510\text{ ft}$

Therefore, your friends should purchase 510 feet of fence and option C is the correct choice.

5 0

2 years ago

Jenny is eight years older then twice her cousin sues age. The sum of their ages is less then 32. What is the greatest age that

maw [93]

Answer:

The age of Sue could be 7 years

Step-by-step explanation:

Jenny is 8 years older than twice her cousin Sue's age.

The first equation will be :

J = 8 + 2S ---------(1)

The sum of their ages is less than 32.

The second equation will be :

J + S < 32 ----------------(2)

Now rearrange both equations :

8 + 2S + S < 32

3S < 32 - 8

3S < 24

S < 24/3

S < 8

S = 7

The age of Sue could be 7 years.

3 0

2 years ago

Suppose the weights of fish caught from pier 1 and pier 2 are normally distributed with equal population standard deviations. Th

madreJ [45]

Answer:

H₀: μ₁ = μ₂ vs, Hₐ: μ₁ > μ₂.

Step-by-step explanation:

A two-sample z-test can be performed to determine whether the claim made by the owner of pier 1 is correct or not.

It is provided that the weights of fish caught from pier 1 and pier 2 are normally distributed with equal population standard deviations.

The hypothesis to test whether the average weights of the fish in pier 1 is more than pier 2 is as follows:

H₀: The weights of fish in pier 1 is same as the weights of fish in pier 2, i.e. μ₁ = μ₂.

Hₐ: The weights of fish in pier 1 is greater than the weights of fish in pier 2, i.e. μ₁ > μ₂.

The significance level of the test is:

α = 0.05.

The test is defined as:

$z=\frac{(\bar x_{1}-\bar x_{2})-(\mu_{1}-\mu_{2})}{\sqrt{\frac{\sigma_{1}^{2}}{n_{1}}+\frac{\sigma_{2}^{2}}{n_{2}}}}$

The decision rule for the test is:

If the p-value of the test is less than the significance level of 0.05 then the null hypothesis will be rejected and vice-versa.

6 0

2 years ago

Andrea has a yard shaped like parallelogram ABCD. The garden area, parallelogram EFGB, has an area of 105 ft2004-05-02-04-00_fil

Lynna [10]

The area of a parallelogram is simply calculated using the formula:

A = b * h

Where,

b = length of the base = 45 ft

h = height which is perpendicular to the base = 21 ft

Using the formula, we calculate the total area of the yard.

A = b* h

A = 45 ft * 21 ft

A = 945 ft^2

Now we don’t want to sod the Garden area for the most obvious reason. The garden has an Area of 105 ft^2, we subtract this to the total area giving us,

Area to sod = 945 ft^2 – 105ft^2

Area to sod = 840 ft^2

5 0

2 years ago