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NARA [144]
2 years ago
11

Mr. Borkowski ordered 3 boxes of pens for the supply room. There are 12 pens in each box. If there are now a total of 96 pens in

the supply room, including the ones Mr.Borkowski added, how many boxes of pens were already in there before his order arrived?
Mathematics
1 answer:
Sloan [31]2 years ago
4 0

Answer:

11 boxes

Step-by-step explanation:

multiply 3 by 12 then add the product of that to 96 pens then divide the sum which is 132 by 12 and you should get 11.

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Which polynomial correctly combines the like terms and expresses the given polynomial in standard form?
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Answer:

D. 3x^4 + x^3y - 8x^2y^2 + 9xy^3 - 13y^4

Step-by-step explanation:

9xy^3 - 4y^4 - 10x^2y^2 + x^3y + 3x^4 + 2x^2y^2 - 9y^4 =

= 9xy^3 - 13y^4 - 8x^2y^2 + x^3y + 3x^4

= 3x^4 + x^3y - 8x^2y^2 + 9xy^3 - 13y^4

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Is 12x=7y-10y a linear equation?
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 <span>12x = 7y-10y 
12x = -3y 
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Compare a pay increase to the inflation rate. Assume that the inflation rate for the past year was 4 percent. You are worried th
Hoochie [10]

The New pay in current year is = $ 2225

The old pay in the last year was = $ 2176

percentage (%) increase formula = (new value- old value ) *100 / old value

which becomes,,

\frac{2225-2176}{2176} *100

which equals to 2.3% .

Hence, the average net pay per month increased is  2.3% .



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A man bought a mobile phone for $800 and sold it for $1000. What was his profit as a percentage of the cost price ​
bija089 [108]

Answer:

1000/800 = 125% profit

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Assume that the number of hours of daylight in New Orleans in 1994 is given by the function D(x) = 7 3 sin 2π 365 x + 35 3 , whe
Bas_tet [7]

Answer:

Here, the given function that represents the number of hours of daylight in New Orleans in 1994 is,

D(x) = \frac{7}{3} \sin \frac{2\pi }{365}x + \frac{35}{3}

Where,

x = the number of days after March 21

The number of days from 1 January to march 21 = 80

If x = -80, then,

D(-80) = \frac{7}{3} \sin \frac{2\pi }{365}(-80) + \frac{35}{3}

            =\frac{7}{3} \sin (-\frac{160 \pi}{365}) + \frac{35}{3}

            =-\frac{7}{3} \sin (\frac{160 \pi}{365}) + \frac{35}{3}

            =-\frac{7}{3}(0.98130)+\frac{35}{3}

           \approx 9.38

Therefore, the number of hours of daylight on January 1 are 9.38.

The number of days from march 21 to may 4 = 44

If x =44, then,

D(44) = \frac{7}{3} \sin \frac{2 \pi}{365}(44) + \frac{35}{3}

         =\frac{7}{3} \sin (\frac{88 \pi}{365}) + \frac{35}{3}

         =\frac{7}{3}(0.6870) + \frac{35}{3}

         \approx 13.27

Therefore, the number of hours of daylight on May 4 are 13.27.

The number of days from October 28 to may 4 = 221

If x = 221, then,

D(221) = \frac{7}{3} \sin \frac{2 \pi}{365}(221) + \frac{35}{3}

           =\frac{7}{3} \sin (\frac{442 \pi}{365}) + \frac{35}{3}

           =\frac{7}{3}(-0.6152)+\frac{35}{3}

           \approx 10.23

Therefore, the number of hours of daylight on October 28 are 10.23.

4 0
2 years ago
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