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2 years ago

If 2a^2 +3^1a - 5a^2= 9, then a-a^2=

Mathematics

1 answer:

anygoal [31]2 years ago

5 0

Answer: 3.

Explanation:

1) Given expression: 2a² + 3a - 5a² = 9

2) Combine like terms: -3a² + 3a = 9

3) Division property of equalities (divide both sides by 3): - a² + a = 3

4) Rearrange: a - a² = 3

That is the answer requested.

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La fuerza necesaria para evitar que un auto derrape en una curva varía inversamente al radio de la curva y conjuntamente con el

Vika [28.1K]

Answer:

768 libras de fuerza

Step-by-step explanation:

Tenemos que encontrar la ecuación que los relacione.

F = Fuerza necesaria para evitar que el automóvil patine

r = radio de la curva

w = peso del coche

s = velocidad de los coches

En la pregunta se nos dice:

La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.

F ∝ 1 / r

Y luego con el peso del auto

F ∝ w

Y el cuadrado de la velocidad del coche

F ∝ s²

Combinando las tres variaciones juntas,

F ∝ 1 / r ∝ w ∝ s²

k = constante de proporcionalidad, por tanto:

F = k × w × s² / r

F = kws² / r

Paso 1

Encuentra k

En la pregunta, se nos dice:

Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.

F = 400 libras

w = 1600 libras

r = 800

s = 50 mph

Tenga en cuenta que desde el

F = kws² / r

400 = k × 1600 × 50² / 800

400 = k × 5000

k = 400/5000

k = 2/25

Paso 2

¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?

F = ?? libras

w = ya que es el mismo carro = 1600 libras

r = 600

s = 60 mph

F = kws² / r

k = 2/25

F = 2/25 × 1600 × 60² / 600

F = 768 libras

Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.

7 0

2 years ago

Which option lists an expression that is not equivalent to 4 2/3?

I am Lyosha [343]

Answer:

Option A and Option B are not equivalent to the given expression.

Step-by-step explanation:

We are given the following expression:

$4^{\frac{2}{3}}$

Applying properties of exponents and base:

$(a^x)^y = a^{xy}\\a^{-x}= (\frac{1}{a})^x\\$

A. Using the exponential property $a^{-x}= (\frac{1}{a})^x\\$ , we can write:

$0.25^{\frac{3}{2}} = (\frac{1}{0.25})^{\frac{-3}{2}} = (4)^{\frac{-3}{2}}$

which is not equal to the given expression.

B. Using the exponential property $a^{-x}= (\frac{1}{a})^x\\$ , we can write:

$(0.25)^{\frac{-3}{2}} = (\frac{1}{0.25})^{\frac{3}{2}} = (4)^{\frac{3}{2}}$

which is not equal to the given expression.

C. First we convert the radical form into exponent form. Then by using the property $(a^x)^y = a^{xy}$ of exponent, we can write the following:

$^3\sqrt{16} = (16)^{\frac{1}{3}} = (4^2)^{\frac{1}{3}} = 4^{\frac{2}{3}}$

which is equal to the given expression.

D. First we convert the radical form into exponent form. Then by using the property $(a^x)^y = a^{xy}$ of exponent, we can write the following:

$(^3\sqrt{4})^2 = (4^{\frac{1}{3}})^2 = 4^{\frac{2}{3}}$

which is equal to the given expression.

Option D and Option C are equivalent to the given expression.

7 0

2 years ago

Read 2 more answers

Solve the equation. Negative StartFraction 9 Over 15 EndFraction y + StartFraction 3 Over 21 EndFraction = StartFraction 5 Over

mina [271]

Answer:

Step-by-step explanation:

9/15y + 3/21 = 5/15 y - 14/21. Adding 14/21 to both sides we then get 9/15y + 17/21 = 5/15y. Subtracting 5/15y from both sides, we get 4/15y + 17/21 = 0.

Then we get 4/15y = -17/21. Dividing by 4/15 gets us -17/21 * 4/15 = -68/315 = y.

4 0

1 year ago

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3/8 divided by -0.25

madreJ [45]

Answer:

thw answer is -3/2 and in decimal form its -1.5

Step-by-step explanation:

hoped I helped:)

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2 years ago

What is the quadratic regression equation that fits these data?

Tresset [83]

Answer:

the answer is a.

Step-by-step explanation:

I plugged your data into a graphing calculator, and got a quad reg in the picture.

5 0

1 year ago

Read 2 more answers