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Crazy boy [7]
2 years ago
6

Which equation is the inverse of y = 100 – x2?

Mathematics
2 answers:
yulyashka [42]2 years ago
7 0

Answer:

The function f be described by

The graph of this function, is the graph of the parent function , which is the parabola with vertex at (0, 0) which opes upwards:

i) reflected with respect to the y-axis, because of the minus

ii) shifted 100 units up

check the picture attached.

A function has an inverse only if it is decreasing or increasing.

So we must divide the following cases for which the inverses exist:

i)  with domain (-infinity, 0]

ii)  with domain [0, infinity)

To find the formula for the inverse function g of f, we use the property:

f(g(x))=x

thus,

so each of - and + cases, are the inverses of

i)  with domain (-infinity, 0]

ii)  with domain [0, infinity)

At this point, recall that the domain of a function, is the range of it's inverse function,

and the range of the function, is the domain of the inverse function.

thus,

the range of , which is [0,infinity) is the domain of

i)  with domain [0,infinity)

So our answer is:

inverse of i)  with domain (-infinity, 0] is

and the inverse of ii)  with domain [0, infinity) is

Step-by-step explanation:

aleksandr82 [10.1K]2 years ago
4 0
The function f be described by y=100- x^{2}

The graph of this function, is the graph of the parent function x^{2}, which is the parabola with vertex at (0, 0) which opes upwards:

i) reflected with respect to the y-axis, because of the minus

ii) shifted 100 units up

check the picture attached. 


A function has an inverse only if it is decreasing or increasing.


So we must divide the following cases for which the inverses exist:

i) y=100- x^{2} with domain (-infinity, 0]

ii) y=100- x^{2} with domain [0, infinity)


To find the formula for the inverse function g of f, we use the property:

f(g(x))=x

thus, 

f(g(x))=x\\\\ 100-[g(x)]^2=x\\\\g^2(x)=100-x\\\\g(x)= \mp\sqrt{100-x}



so each of - and + cases, are the inverses of 


i) y=100- x^{2} with domain (-infinity, 0]

ii) y=100- x^{2} with domain [0, infinity)


At this point, recall that the domain of a function, is the range of it's inverse function, 

and the range of the function, is the domain of the inverse function.

thus, 

the range of \sqrt{100-x}, which is [0,infinity) is the domain of 

i) y=100- x^{2} with domain [0,infinity)



So our answer is:

inverse of i) y=100- x^{2} with domain (-infinity, 0] is -\sqrt{100-x}


and the inverse of ii) y=100- x^{2} with domain [0, infinity) is 

\sqrt{100-x}

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The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig
Troyanec [42]

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

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Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

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aleksley [76]
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Find a b if a = 3i + 8j and b = -0.5i -4j.
Gekata [30.6K]

Answer:

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Step-by-step explanation:

So this is a dot products vector problem, so the i and j represent x and y or horizontal and vertical components. So you multiple 3i and -0.5i and then separately multiply 8j and -4j. You get -1.5 and -32. Now all you have to do is add them and you get -33.5.

Basically in short:

1. Multiply the “i’s”.

2. Multiply the “j’s”.

3. Add the two products together.

HOPE THIS HELPS !! :-)

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Thus, we just need to find when h = 0 so that we find when it hits the ground.

0 = -4.9t² + 19.6t + 58.8
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