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miv72 [106K]
2 years ago
14

5y-6=3y-20 how do i solve this problem

Mathematics
2 answers:
Studentka2010 [4]2 years ago
8 0
Im guessing its asking what y equals, subtract 3y from each side, the result is 2y-6=-20, add six to each side to get 2y=-14, divide each side by 2, the answer is.....
Y= -7
rusak2 [61]2 years ago
7 0
Minus 3y both sides
2y-6=-20
add 6 to both sids
2y=-14
divide 2
y=-7
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A process engineer is implementing a quality assurance system on a breakfast cereal production line. A new sensor is installed o
nataly862011 [7]

Answer:

0.2%

Step-by-step explanation:

The given parameters are;

The percentage of product within the correct range = 95%

The percentage of the times the sensor reject boxes of incorrect weight = 98%

The percentage of the times the company reject boxes with correct weight = 1%

\begin{array}{cccc}&P&N&T\\P&TP&0.9&90\\N&FP&9.8&10\end{array}

We have, FN = 0.9, TN = 9.8, TP = 90 - 0.9 = 89.1, FP = 10 - 9.8 = 0.2

FNR = FN/(FN + TP) = 0.9/(0.9 + 89.1) = 0.01

FPR = 0.2/(0.2 + 9.8) = 0.02

TPR = 89.1/(89.1 + 0.9) = 0.99

TNR = 9.8/(9.8 + 0.2) = 0.98

P(C/A) = TPR × P(C)/((TPR × P(C) + FPR×(1 - P(C)))

Where;

P(C/A) = The probability that a correct weight package is accepted

∴ P(C/A) = 0.99*0.9/(0.99*0.9 + 0.02*0.1) ≈ 0.99776

The probability that a correctly weighed package is rejected, P(C/R), is given as follows;

P(C/R) = 1 - P(C/A)

∴ P(C/R) ≈ 1 - 0.99776 = 0.00224 ≈ 0.2%

The probability that a correctly weighed package is rejected, P(C/R) ≈ 0.2%

5 0
2 years ago
A function of the form f(x) = abx is modified so that the b value remains the same but the a value is increased by 2. How do the
olga nikolaevna [1]

Answer:

The range stays the same.

The domain stays the same.  

Step-by-step explanation:

The function f(x)=ab^{x} is an exponential function, where <em>a</em> is the coefficient, <em>b</em> is the base and <em>x</em> is the exponent.

The domain for this kind of functions is: All real numbers.

And the range is: (0,∞); this happen because the exponential functions are always positive when <em>a</em>>0.

Therefore, if the value of <em>a</em> is increased by 2, the domains will stay the same and the range will stay the same: (0,∞). The coefficient does not change the domain or the range if it keeps the same sign.

6 0
2 years ago
Read 2 more answers
The graphs below have the same shape. The equation of the blue graph is f(x) = 2x. Which of these is the equation of the red gra
Allisa [31]
The main thing you want to ask yourself is "What is the difference between the two graphs?"

As we can see, the graphs look identical in every way except that g(x) is lower than f(x).

This means that the graph is shifted down a certain amount.

If we look at the y-intercepts of the two functions, we see that f(x) has a y-intercept of 1, and g(x) has a y-intercept of -1.

This means that f(x) is two units lower than g(x).

The y-intercept of a function can be changed by adding or subtracting a number to the original function (in this case 2^{x}).

Because the graph f(x) is 2 lower than the graph of g(x), we can find g(x) by subtracting 2 from f(x).

Therefore, g(x) = 2^{x} - 2.
4 0
2 years ago
The figure below shows a parallelogram ABCD. Side AB is parallel to side DC and side AD is parallel to side BC: A quadrilateral
il63 [147K]
The postulate that is used in order to prove the congruency of the triangles is the ASA which means (Angle – Side – Angle). The property that is applicable for the congruency of DB to itself is the reflexive property. Therefore, the answer to this item is the second choice. 
 Hope I helped! :)
6 0
2 years ago
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Brock is training for a Crossfit competition. He began the training completing pull-ups and box jumps origanally, his training p
siniylev [52]

If the adjusted ratio was 2:7, then

2x is the number of pull-ups

and

7x is the number of box jumps.

You can state that since he completed 63 box jumps at the end of his training, then

7x=63,

x=9

and

2x=18.

The total number of exercises performed is 2x+9x=18+63=81.

As at start the ratio was 5:4, then

5y was the number of pull-ups

and

4y was the number of box jumps.

Therefore, 5y+4y=81,

9y=81,

y=9

and 5y=45, 4y=36.

Answer: Initially: 45 pull-ups and 36 box jumps. At the end: 18 pull-ups and 63 box jumps.

8 0
2 years ago
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