5y-6=3y-20 how do i solve this problem
2 answers:
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Answer:
Help
Step-by-step explanation:
Let's call the lengths of our two types of sides <em />
and 
.
The two sides will that our 1.3 inches bigger than the third side will be have length x, and the length of the other side will be known as y. Thus,
.
Considering this, we can add our sides together and set this value equal to 8, given the information in the problem:
Now, let's solve for y.
Now, we are not done yet. We must determine the true lengths of all of our sides. Using the equation we found earlier, the length of the two bigger sides is
inches and the length of our smaller side is simply 
inches.
To verify, we can add these sides together and check that they equal 8:
3.1 + 3.1 + 1.8 = 8 ✔
The two sides will that our 1.3 inches bigger than the third side will be have length x, and the length of the other side will be known as y. Thus,
Considering this, we can add our sides together and set this value equal to 8, given the information in the problem:
Now, let's solve for y.
Now, we are not done yet. We must determine the true lengths of all of our sides. Using the equation we found earlier, the length of the two bigger sides is
To verify, we can add these sides together and check that they equal 8:
3.1 + 3.1 + 1.8 = 8 ✔
Answer:
A) Approximate percentage of women with platelet counts within 2 standard deviations of the mean, or between 118.5 and 377.3 = 95%
B) approximate percentage of women with platelet counts between 53.8 and 442.0 = 99.7%
Step-by-step explanation:
We are given;
mean;μ = 247.9
standard deviation;σ = 64.7
A) We want to find the approximate percentage of women with platelet counts within 2 standard deviations of the mean, or between 118.5 and 377.3.
Now, from the image attached, we can see that from the empirical curve, the probability of 1 standard deviation from the mean is (34% + 34%) = 68 %.
While probability of 2 standard deviations from the mean is (13.5% + 34% + 34% + 13.5%) = 95%
Thus, approximate percentage of women with platelet counts within 2 standard deviations of the mean, or between 118.5 and 377.3 = 95%
B) Now, we want to find the approximate percentage of women with platelet counts between 53.8 and 442.0.
53.8 and 442.0 represents 3 standard deviations from the mean.
Let's confirm that.
Since mean;μ = 247.9
standard deviation;σ = 64.7 ;
μ = 247.9
σ = 64.7
μ + 3σ = 247.9 + 3(64.7) = 442
Also;
μ - 3σ = 247.9 - 3(64.7) = 53.8
Again from the empirical curve attached, we cans that at 3 standard deviations from the mean, we have a percentage probability of;
(2.35% + 13.5% + 34% + 34% + 13.5% + 2.35%) = 99.7%
