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2 years ago

What term best describes the intersection of the strokes drawn when writing the letter T? point plane line

Mathematics

1 answer:

Anna11 [10]2 years ago

4 0

Answer:

Point just took the test and this is the answer.

Step-by-step explanation:

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The number of hours walked varies inversely with the speed of the walker. if it takes sam 12 hours to complete his walking goal

Effectus [21]

We let k be the proportionality constant for the relationship between number of hours, h and speed of the walker, s.

h = k/s
Substituting the known values,
12 = k/5
k = 60

For the second scenario,
h = k/s
Substituting the calculated value for k and the given value for speed,
h = (60)(3 miles/hour)
h = 20 hours
h = 20 hours

Therefore, it will take 20 hours to walk with a speed of 3 miles per hour.

7 0

2 years ago

A particle travels 24.6 km in 30 minutes. Find the

tatyana61 [14]

Answer:

See the solutions below

Step-by-step explanation:

Given data

Distance = 24.6km

in meters= 24.6*1000= 24600m

time= 30 minutes

in seconds= 30*60= 1800

int hours= 0.5 hour

speed of the particle in

(i) km/h= 24.6/0.5= 49.2 km/h

(ii) m/s.= 24600/ 1800= 13.66 m/s

8 0

1 year ago

Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 24 feet,

masha68 [24]

Well the sides of these 2 quadrilaterals are proportional to each other , so you would have to find the scale factor of the 2 then see which sides have already proportional pairs , then multiply *or / to find the last one .

Answer: D. 11.7 ft

5 0

2 years ago

Read 2 more answers

Write a expression that shows 3 times the sixth power of 10

user100 [1]

(10 raised to the power of 6)×3

(10*6) ×3

8 0

2 years ago

The number of flaws in a fiber optic cable follows a Poisson distribution. It is known that the mean number of flaws in 50m of c

boyakko [2]

Answer:

(a) The probability of exactly three flaws in 150 m of cable is 0.21246

(b) The probability of at least two flaws in 100m of cable is 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063

Step-by-step explanation:

A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by

$p(x;\lambda)=\frac{\lambda e^{-\lambda}}{x!}$ for x = 0, 1, 2, ...

where $\lambda$ , the mean number of successes.

(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is $1.2 \cdot 3 =3.6$

The probability of exactly three flaws in 150 m of cable is

$P(X=3)=p(3;3.6)=\frac{3.6^3e^{-3.6}}{3!} \approx 0.21246$

(b) The probability of at least two flaws in 100m of cable is,

we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is $1.2 \cdot 2 =2.4$

$P(X\geq 2)=1-P(X$

$P(X\geq 2)=1-p(0;2.4)-p(1;2.4)\\\\P(X\geq 2)=1-\frac{2.4^0e^{-2.4}}{0!}-\frac{2.4^1e^{-2.4}}{1!}\\\\P(X\geq 2)\approx 0.69155$

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is

$P(X=1)=p(1;1.2)=\frac{1.2^1e^{-1.2}}{1!}\\P(X=1)\approx 0.36143$

The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is

$(0.36143)(0.36143) = 0.13063$

4 0

2 years ago