I agree with Marita, that the angles could have the same measure. This can be proven if you set the two amounts equal and solve for x.
9x - 25 + x = x + 50 + 2x - 12
To begin, we should combine like terms on both sides of the equation to start simplifying the equation.
10x - 25 = 3x + 38
Next, we should subtract 3x from both sides and add 25 to both sides to get the variable x alone on the left side of the equation.
7x = 63
Finally, we should divide both sides by 7, to get rid of the coefficient of x.
x = 9
If you plug in 9 for x in our first equation, you get that both of the angle measurements equal 65 degrees. This means that Marita is correct, because if x = 9, then the angles would have the same measure.
A)<span> How much would it cost to ship a package weighing 3.2 pounds? Explain how you arrived at your answer.
Answer:Shipping cost of 3.2 package is $4.13.
</span>We can't use the cost assigned to 3 lbs because the package is over 3 lbs but it is not over 4 lbs so we use the cost of 4lbs. (check the attachment for price)
b)<span>What type of graph is needed to represent the Media Mail shipping prices as a function of the weight of the books shipped? Explain your thinking.
Answer:Line graph </span>is needed to represent the Media Mail shipping prices as a function of the weight of the books shipped.
In line graph, x values represent the weight in pounds and the y values represent the cost.
c)<span>Graph the Media Mail shipping prices as a function of the weight of the books shipped.
Answer;When we g</span>raph the Media Mail shipping prices as a function of the weight of the books shipped, it will be;
f(x) = 2.69 + 0.48(x-1)
5 people.
14 + 9 + 12 + 13 + 12 = 60 total pencils.
60 pencils / 5 people = 12 pencils each.
9514 1404 393
Answer:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
142 fish
Step-by-step explanation:
A) The differential equation is modified by adding a -50 fish per year constant term:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
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B) The steady-state value of the fish population will be when N reaches the value that makes dN/dt = 0.
(0.4/1200)(N)(1200-N) -50 = 0
N(N-1200) = -(50)(1200)/0.4) . . . . rewrite so N^2 has a positive coefficient
N^2 -1200N + 600^2 = -150,000 +600^2 . . . . complete the square
(N -600)^2 = 210,000 . . . . . simplify
N = 600 + √210,000 ≈ 1058
This steady-state number of fish is ...
1200 - 1058 = 142 . . . . below the original carrying capacity