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prohojiy [21]
2 years ago
13

Nick has to build a brick wall. Each row of the wall requires 62 bricks. There are 10 rows in the wall. How many bricks will Nic

k require to build the wall?
102 × 6
106
610
10 × 62
Mathematics
1 answer:
Delicious77 [7]2 years ago
7 0
10 x 62 is the equation for this problem because every row has 62 and there are 10 rows.
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Two consecutive integers are such that 3 times the larger exceeds twice the smaller by 34. find the integers.
julsineya [31]

x - a smaller number

(x+1) - a larger number

3(x+1) - 2x = 34

3x + 3 - 2x = 34

x= 31

(x+1) = 32

7 0
2 years ago
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What is the simplified value of the expression below rounded to the nearest hundredth? StartFraction 3.5 times 2 + 9 over 10.4 m
miskamm [114]

Answer:

The answer is 2.11~! I hope I helped <3

Step-by-step explanation:

3.5x2=7   7+9=16   1.4x2=2.8   10.4-2.8=7.6   16/7.6=2.10526315789

but we simplify so, 2.10526315789 rounded to the nearest hundredth is 2.11~!

 

7 0
2 years ago
Katie wants to create a rectangular frame for a picture. She has 60 inches of material. If she wants the length to be 3 more tha
Fofino [41]

Answer:

Largest possible length is <em>21 inches</em>.

Step-by-step explanation:

Given:

Total material available = 60 inches

Length to be 3 more than twice of width.

To find:

Largest possible length = ?

Solution:

As it is rectangular shaped frame.

Let length = l inches and

Width = w inches

As per given condition:

l = 2w+3 ..... (1)

Total frame available = 60 inches.

i.e. it will be the perimeter of the rectangle.

Formula for perimeter of rectangle is given as:

P = 2 \times (Width + Length)

Putting the given values and conditions as per equation (1):

60 = 2 \times (w+ l)\\\Rightarrow 60 = 2 \times (w+ 2w+3)\\\Rightarrow 60 = 2 \times (3w+3)\\\Rightarrow 30 = 3w+3\\\Rightarrow 3w = 27\\\Rightarrow w = 9 \ inch

Putting in equation (1):

l = 2\times 9+3\\\Rightarrow l = 21\ inch

So, the answer is:

Largest possible length is <em>21 inches</em>.

6 0
2 years ago
Suppose that the probability density function for the length x in feet of some type of fish caught by sport fishermen is given b
Firdavs [7]

Answer:

The probability that a fish caught by a fisherman is between 0.25 feet and 2 feet long is 0.4375.

Step-by-step explanation:

The probability density function or p.d.f. for the length <em>x,</em> in feet, of some type of fish caught by sport fishermen is :

p(x) = \left \{{{(\frac{1}{4})\ ;\  0\leq x\leq 4 } \atop{0\ ;\ otherwise} \right.

The probability that a fish caught by a fisherman is between 0.25 feet and 2 feet long is:

P(0.25\leq X\leq 2)=\int\limits^{0.25}_{2} {(\frac{1}{4})} \, dx \\=|(\frac{1}{4})x|^{2}_{0.25}\\=(\frac{1}{4})(2-0.25)\\=0.4375

Thus, the probability that a fish caught by a fisherman is between 0.25 feet and 2 feet long is 0.4375.

8 0
2 years ago
Mrs.thapa bought 150 kg of oranges.18 kg of oranges were rotten and not fit for selling.If she sold the remaining quantity of or
kogti [31]

Answer:

Rs.64

Step-by-step explanation:

<u>Amount of oranges:</u>

  • 150 kg

<u>Oranges sold:</u>

  • 150 - 18 = 132 kg

<u>Money made:</u>

  • 132* 80 = Rs. 10560

<u>Selling price of 150 kg:</u>

  • 10560/150 = Rs. 70.4

<u>Cost price:</u>

  • x+10% = 70.4
  • x*1.1= 70.4
  • x= 70.4/1.1
  • x= Rs.64
  • Cost price of oranges= Rs. 64
3 0
2 years ago
Read 2 more answers
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