answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Keith_Richards [23]
1 year ago
8

The cell phone company decided to collect similar data but this time they collected information of texting speed according to ag

e. Use the process of creating a scatter plot to describe how to create a scatterplot of the new data.

Mathematics
2 answers:
Ludmilka [50]1 year ago
7 0

Step-by-step explanation:

As we know, Scatter plots resembles line graphs in that they are plotted on the x and y axis and the purpose of a scatter plot is to shows if the variables are related to each other. If yes, they can draw a line of best fit which can expose or go through most of the points in the plot.

Given the information in the question, we know:

"they collected information of texting speed according to age"

=> We have 2 variables here which are age and (texting speed)

Step 1:

  • Label the x-axis the input variable (age)
  • Label the y-axis the output variable (texting speed)

Step 2: Plot the points according to age and texting speed

Hence, from that plot, it could have two cases in the relation of age and texting speed which are "the more time, more text is written", or "the less time, more text is written".

navik [9.2K]1 year ago
7 0

Answer:

Label axes according to input and output variables. Plot the ordered pair of the independent and dependent variable on the coordinate plane. Identify if there is a relationship between the variables.

Step-by-step explanation:

You might be interested in
A pond forms as water collects in a conical depression of radius a and depth h. Suppose that water flows in at a constant rate k
Scrat [10]

Answer:

a. dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. πa² ≥ k/∝

Step-by-step explanation:

a.

The rate of volume of water in the pond is calculated by

The rate of water entering - The rate of water leaving the pond.

Given

k = Rate of Water flows in

The surface of the pond and that's where evaporation occurs.

The area of a circle is πr² with ∝ as the coefficient of evaporation.

Rate of volume of water in pond with time = k - ∝πr²

dV/dt = k - ∝πr² ----- equation 1

The volume of the conical pond is calculated by πr²L/3

Where L = height of the cone

L = hr/a where h is the height of water in the pond

So, V = πr²(hr/a)/3

V = πr³h/3a ------ Make r the subject of formula

3aV = πr³h

r³ = 3aV/πh

r = ∛(3aV/πh)

Substitute ∛(3aV/πh) for r in equation 1

dV/dt = k - ∝π(∛(3aV/πh))²

dV/dt = k - ∝π((3aV/πh)^⅓)²

dV/dt = K - ∝π(3aV/πh)^⅔

dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. Equilibrium depth of water

The equilibrium depth of water is when the differential equation is 0

i.e. dV/dt = K - ∝π(3a/πh)^⅔V^⅔ = 0

k - ∝π(3a/πh)^⅔V^⅔ = 0

∝π(3a/πh)^⅔V^⅔ = k ------ make V the subject of formula

V^⅔ = k/∝π(3a/πh)^⅔ -------- find the 3/2th root of both sides

V^(⅔ * 3/2) = k^3/2 / [∝π(3a/πh)^⅔]^3/2

V = (k^3/2)/[(∝π.π^-⅔(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝π^⅓(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝^3/2.π^½.(3a/h))]

V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. Condition that must be satisfied

If we continue adding water to the pond after the rate of water flow becomes 0, the pond will overflow.

i.e. dV/dt = k - ∝πr² but r = a and the rate is now ≤ 0.

So, we have

k - ∝πa² ≤ 0 ---- subtract k from both w

- ∝πa² ≤ -k divide both sides by - ∝

πa² ≥ k/∝

5 0
2 years ago
Three judges measure the lap times of a runner and each measurement is different from the others by a few hundredths of a second
ohaa [14]

Answer:

Systematic error

Step-by-step explanation:

Assuming that none of the judges are biased, the most likely reason for this difference is the occurrence of systematic errors.

Systematic errors are errors introduced by inaccuracy in the experimental design, be it in the observation or measurement process.

In this case, the reaction time from observing the finish and stopping the clock for each judge might be different, which configures a systematic error.

6 0
1 year ago
Three assembly lines are used to produce a certain component for an airliner. To examine the production rate, a random sample of
nikitadnepr [17]

Answer:

a) Reject H₀

b) [0.31; 3.35]

Step-by-step explanation:

Hello!

a) The objective of this example is to compare if the population means of the production rate of the assembly lines A, B and C. To do so the data of the production of each line were recorded and an ANOVA was run using it.

The study variable is:

Y: Production rate of an assembly line.

Assuming that the study variable has a normal distribution for each population, the observations are independent and the population variances are equal, you can apply a parametric ANOVA with the hypothesis:

H₀ μ₁= μ₂= μ₃

H₁: At least one of the population means is different from the others

Where:

Population 1: line A

Population 2: line B

Population 3: line C

α: 0.01

This test is always one-tailed to the right. The statistic is the Snedecor's F, constructed as the MSTr divided by the MSEr if the value of the statistic is big, this means that there is a greater variance due to the treatments than to the error, this means that the population means are different. If the value of F is small, it means that the differences between populations are not significant ( may differ due to error and not treatment).

The critical region is:

F_{k-1;n-k; 1-\alpha } = F_{2;15; 0.99} = 6.36

If F ≥ 3.36, the decision is to reject the null hypothesis.

Looking at the given data:

F= \frac{MSTr}{MSEr}= 11.32653

With this value the decision is to reject the null hypothesis.

Using the p-value method:

p-value: 0.001005

α: 0.01

The p-value is less than the significance level, the decision is to reject the null hypothesis.

At a level of 5%, there is significant evidence to say that at least one of the population means of the production ratio of the assembly lines A, B and C is different than the others.

b) In this item, you have to stop paying attention to the production ratio of the assembly line A to compare the population means of the production ratio of lines B and C.

(I'll use the same subscripts to be congruent with part a.)

The parameter to estimate is μ₂ - μ₃

The populations are the same as before, so you can still assume that the study variables have a normal distribution and their population variances are unknown but equal. The statistic to use under these conditions, since the sample sizes are 6 for both assembly lines, is a pooled-t for two independent variables with unknown but equal population variances.

t=  (X[bar]₂ - X[bar]₃) - ( μ₂ - μ₃) ~t_{n_2+n_3-2}

Sa√(1/n₂+1/n₃)

The formula for the interval is:

(X[bar]₂ - X[bar]₃) ± t_{n_2+n_3-2; 1 - \alpha /2}* Sa\sqrt{*\frac{1}{n_2} + \frac{1}{n_3} }

Sa^{2} = \frac{(n_2-1)*S_2^2+ (n_3-1)*S_3^2}{n_2+n_3-2}

Sa^{2} = \frac{(5*0.67)+ (5*0.7)}{6+6-2}

Sa^{2} = 0.685

Sa= 0.827 ≅ 0.83

t_{n_2+n_3-2;1-\alpha /2}= t_{10;0.995} = 3.169

X[bar]₂ = 43.33

X[bar]₃ = 41.5

(43.33-41.5) ± 3.169 * *0.83\sqrt{*\frac{1}{6} + \frac{1}{6} }

1.83 ± 3.169 * 0.479

[0.31; 3.35]

With a confidence level of 99% you'd expect that the difference of the population means of the production rate of the assemly lines B and C.

I hope it helps!

8 0
1 year ago
The grade point average (GPA) of the students at Lakeview High School is normally distributed with a mean of 3.1 and a standard
Morgarella [4.7K]
Approximately 1718 have a score within that range.

We calculate the z-score for each end of this spectrum:

z = (X-μ)/σ = (2.5-3.1)/0.3 = -0.6/0.3 = -2

Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this z-score is 0.0228.

For the upper end:
z = (3.7-3.1)/0.3 = 0.6/0.3 = 2

Using a z-table, we see that the area to the left of, less than, this z-score is 0.9772.

The probability between these is given by subtracting these:
0.9772 - 0.0228 = 0.9544.

This means the proportion of people that should fall between these is 0.9544:
0.9544*1800 = 1717.92 ≈ 1718
4 0
1 year ago
Match each set of prices with the correct percent of increase or decrease.
cricket20 [7]
<span>Take the
(original price - new price)/original price
then multiply by 100
If it is a positive number, it is a decrease.
If it is a negative number, it is an increase.

original price: $63.00
new price: $56.07
11% decrease

</span><span>original price: $12.25
new price: $13.23
</span><span>8% increase
</span>
<span>original price: $98.00
new price: $108.78
</span>11% increase

<span>original price: $37.50
new price: $34.50
8% decrease</span>
7 0
1 year ago
Other questions:
  • Which of the following is a result of shifting a circle with equation (x+3)^2+(y-2)^2=36 up 3 units
    9·2 answers
  • Given two vectors a⃗ =4.00i^+7.00j^ and b⃗ =5.00i^−2.00j^ , find the vector product a⃗ ×b⃗ (expressed in unit vectors). what is
    11·2 answers
  • James has t toy cars and Paul has 13 more. How many cars will James have if Paul gives him half of his cars?
    12·1 answer
  • Byron purchased a box of candy at the store.On his way home he ate 1/4 of the candy in the box.At dinner with friends later that
    15·2 answers
  • A battery factory typically produces 12,000 batteries per day and uses 50 boxes for packing the batteries. If the number of boxe
    11·1 answer
  • Errol's bike ride from home to school can be modeled by the equation d(t) = - 1/4 * t + 2 where d(t) is his distance from school
    11·1 answer
  • 1).He gastado 5/8 de mi dinero. Si en lugar de gastar los 5/8 hubiera gastado los 2/5 de mi dinero, tendria ahora 72 soles mas d
    13·1 answer
  • What is the slope of a line perpendicular to the line whose equation is 3x-12y=2163x−12y=216.
    9·2 answers
  • 261, 256, 251, ...<br> Find the 46th term
    14·2 answers
  • (b) Amira takes 9 hours 25 minutes to complete a long walk. (i) Show that the time of 9 hours 25 minutes can be written as 113 1
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!