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satela [25.4K]
2 years ago
12

Which expression is equivalent to 3sqrtx^5y?

Mathematics
1 answer:
slamgirl [31]2 years ago
3 0

Answer:

The correct option is B.

Step-by-step explanation:

The given expression is

\sqrt[3]{x^5y}

\sqrt[3]{x^5y}=(x^5y)^{\frac{1}{3}}      [\because \sqrt[n]{x}=x^{\frac{1}{n}}]

\sqrt[3]{x^5y}=(x^5)^{\frac{1}{3}}y^{\frac{1}{3}}      [\because (mn)^x=m^xn^x]

\sqrt[3]{x^5y}=x^{\frac{5}{3}}y^{\frac{1}{3}}      [\because (x^m)^n=x^{mn}]

Therefore option B is correct.

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A lock has 5 buttons. The lock is opened by pushing two buttons simultaneously and then by pushing one button alone. How many co
Pavel [41]

We first must calculate how many ways 2 oblects can be chosen from 5.

combinations = 5! / 2! * (5-2)!

combinations = 5*4 / 2

combinations = 10


There are 10 ways to choose the 2 buttons and 5 ways to choose the final butto so there are 10 * 5 = 50 different ways.


Source

1728.com/combinat.htm




7 0
1 year ago
Kimberly is considering buying her first home. The house she is interested in buying is priced at $159,000. Kimberly qualifies f
lbvjy [14]
829.00    I just used a mortgage calculator 
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1 year ago
Read 2 more answers
Given your sister's incomplete text,
egoroff_w [7]

Explanation:

Quadrants 2 and 3 houses points that have negative x-values, while as Quadrants 1 and 4 houses points that have positive x-values.

If 'your sister' completes the text with negative y-value, the point would be in Q3.

If 'your sister' completes the text with positive y-value, the point would be in Q2.

8 0
2 years ago
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Four different prime numbers, each less than 20, are multiplied together. What is greatest possible result?
valentinak56 [21]

Answer:

46,189

Step-by-step explanation:

The prime numbers that are less than 20 are :

1,2,3,5,7,11,13,17,19

to get the greatest value, we multiply the four numbers with the largest values i.e

11 x 13 x 17 x 19 = 46,189

8 0
2 years ago
The speed of a sparrow is x km/h in still air. When the
Semmy [17]

Answer:

x = 5m/s

Step-by-step explanation:

Distance flying out = 12 km  (headwind)

Distance flying back = 12 km (tailwind)

total distance = 12 + 12 =24 km

wind speed = 1km/h

speed going out (with headwind) = (x - 1) km/h

speed coming back (with tailwind) = (x + 1) km/h

Time taken to go out = distance going out / speed going out

= 12 / (x-1)

Time taken to come back = distance coming back / speed coming back

= 12 / (x+1)

total time = time taken to go out + time taken to come back

5 =[ 12/(x-1) ] + [ 12/(x-1)]

expanding this, we will get

5x² - 24x - 5 = 0

solving quadratic equation, we will get

x = -1/5 (impossible because speed cannot be negative)

or

x = 5 (answer)

4 0
2 years ago
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