Answer:
b. 2-independent sample t-test
Correct for this case is the best test since the result from each group are independent and we can compare the sample means between th two groups
Step-by-step explanation:
For this case the intention is try to test if scores on a test of science achievement differ for female and male 8th grade students. let's analyze the possible options for this case:
a. 2-dependent sample t-test
False is not possible since the nature of the gender is not possible to conclude tha the results from boys and girls are dependent
b. 2-independent sample t-test
Correct for this case is the best test since the result from each group are independent and we can compare the sample means between the two groups
c. Correlation
False we can't compare the means of interest with a correlation coefficient since that's not the purpose of the study
d. 2-way ANOVA
False we have just one variable between two groups so is not possible to apply a 2 way ANOVA
Answer:
BD = 4.99 units
Step-by-step explanation:
Consider the triangle ABD only.
The angle formed is 31 degrees which occurs between two sides that are AD and BC.
We know that for a right angled triangle, the angle can always be taken as an angle between hypotenuse and base.
Thus, The perpendicular sides is then 3 units, where base is BD and Hypotenuse is AD
Using formula for tanθ
tanθ = Perpendicular/Base
tan31 = 3/BD
0.601 = 3/BD
BD = 3/0.601
BD = 4.99 units
Answer:
11.75 feet
Step-by-step explanation:
17 times 12 = 204 inches
204 - 63 = 141 inches
141/12 = 11.75 feet
Answer:
Step-by-step explanation:
2n+15>3
The probability of picking one girl would be
. That is because there are 5 girls out of the 12 students, and the probability of an event occuring is:
.
Using that same logic, the next student should be easier. We reduced the student population by 1, so we have 11 possible ways it can happen now instead of 12, so that gives us:
, for the probability of picking a boy as the second pick.
And lastly, using the same logic shown above, the probability of picking a girl on the third pick would be:
.
We are not done, though. We have the separate probabilities, but now we have to multiply then together to figure out the probability of this exact event happening:

Which when reduced is:
