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pantera1 [17]
1 year ago
9

Polygon v has an area of 1 square unit. Jun-seo drew a scaled version of polygon v using a scale factor of 7 and labeled it poly

gon w
Mathematics
2 answers:
Liula [17]1 year ago
8 0

Answer:

49 units

Step-by-step explanation:

khan academy

son4ous [18]1 year ago
3 0

Answer:

The area of Polygon

W

WW is

49

4949 square units.

Step-by-step explanation: dk

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Your cell phone plan charges a base charge each month plus a charge per daytime minute of usage and December used 510 daytime mi
algol13

Answer:

In February, 423 daytime minutes is used

Step-by-step explanation:

Let the base plan charges be x

And cost per daytime minute be y

In December,

x  + 510y =  92.25------------------(1)

In January,

x + 397y = 77.56---------------------(2)

Subtracting eq(2) from eq(1)

x  + 510y =  92.25

x + 397y = 77.56

-------------------------------

0  + 113y = 14.69

-------------------------------

y = \frac{14.69}{113}

y =  0.13----------------------------------(3)

Substituting (3) in (1)

x  + 510(0.13) =  92.25

x + 66.3 = 92.25

x = 92.25 - 66.3

x = 25.95

So In February

base plan  + (daytime minute)(cost per daytime minute) = 80.9

25.95 + (daytime minute)(0.13) = 80.9

(daytime minute)(0.13) = 80.9 - 25.95

(daytime minute)(0.13) = 54.95

(daytime minute) =\frac{54.95}{0.13}

daytime minutes = 422.69

daytime minute  \approx 423

3 0
2 years ago
People are arriving at a party one at a time. While waiting for more people to arrive they entertain themselves by comparing the
Marina CMI [18]

Answer:

=(k−1)*P(X>k−1) or (k−1)365k(365k−1)(k−1)!

Step-by-step explanation:

First of all, we need to find PMF

Let X = k represent the case in which there is no birthday match within (k-1) people

However, there is a birthday match when kth person arrives

Hence, there is 365^k possibilities in birthday arrangements

Supposing (k-1) dates are placed on specific days in a year

Pick one of k-1 of them & make it the date of the kth person that arrives, then:

The CDF is P(X≤k)=(1−(365k)k)/!365k, so the can obtain the PMF by  

P(X=k) =P (X≤k) − P(X≤k−1)=(1−(365k)k!/365^k)−(1−(365k−1)(k−1)!/365^(k−1))=

(k−1)/365^k * (365k−1) * (k−1)!

=(k−1)*(1−P(X≤k−1))

=(k−1)*P(X>k−1)

6 0
2 years ago
On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 3, 1) and (0, 3). Everything to th
Allushta [10]

Answer:

y>\frac{2}{3}x+3

Step-by-step explanation:

step 1

Determine the slope of the dashed line

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have

(-3,1) and (0,3)

substitute

m=\frac{3-1}{0+3}

m=\frac{2}{3}

step 2

Find the equation of the dashed line in slope intercept form

y=mx+b

we have

m=\frac{2}{3}

b=3 ---> given problem

substitute

y=\frac{2}{3}x+3

step 3

Find the equation of the inequality

we know that

Is a dashed line and everything to the left of the line is shaded

so

y>\frac{2}{3}x+3

see the attached figure to better understand the problem

8 0
1 year ago
Read 2 more answers
The value of a gold coin picturing the head of the Roman Emperor Vespasian is increasing at the rate of 5% per year. If the coin
bazaltina [42]

Answer:

255.75

Step-by-step explanation:

6 0
1 year ago
Read 2 more answers
Brant is preparing for the upcoming track season, and he wants to reduce the time of his 1-mile run. Last year, he conducted an
Ivanshal [37]

The Q30X program and the Intensity program are both effective because the average participant 1-mile run time was reduced for each program, but the Intensity program is the more effective program because it yielded a greater decrease in the average participant 1-mile run time.

5 0
2 years ago
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