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amm1812
2 years ago
12

Hiromi sells 12 T-shirts each week at a price of $13.00. Past sales have shown that for every $0.25 decrease in price, 4 more T-

shirts are sold. Knowing that revenue is a product of price and quantity, Hiromi models his revenue by R(x) = (13 - 0.25x)(12 + 4x), where x represents the number of times there is a reduction in price.
Question: What is the maximum revenue Hiromi can generate each week? Show work.
Mathematics
1 answer:
Lerok [7]2 years ago
4 0
(13-0.25x4)(12+4x4)=2,464
(13-0.25x5)(12+4x5)=3,845
(13-0.25x6)(12+4x6)=2,845
so your answer is 3,845 because if Hirome sells them for $11.75 he makes $3845 if Hirome sold them for $11.50 he makes $2845.80 and if he sold them for $12.00 he would make $2464.00

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Factor the polynomial expression 15x^2 - 2x - 8
AVprozaik [17]

Answer:

(3 x + 2) (5 x - 4)

Step-by-step explanation:

Factor the following:

15 x^2 - 2 x - 8

Factor the quadratic 15 x^2 - 2 x - 8. The coefficient of x^2 is 15 and the constant term is -8. The product of 15 and -8 is -120. The factors of -120 which sum to -2 are 10 and -12. So 15 x^2 - 2 x - 8 = 15 x^2 - 12 x + 10 x - 8 = 5 x (3 x + 2) - 4 (3 x + 2):

5 x (3 x + 2) - 4 (3 x + 2)

Factor 3 x + 2 from 5 x (3 x + 2) - 4 (3 x + 2):

Answer: (3 x + 2) (5 x - 4)

4 0
2 years ago
The prices of three t-shirts styles are $24, $30 and $36. the probability of choosing a $24 t-shirt is 1/6. the probability of c
Slav-nsk [51]

\text{Answer} : \text{The expected value of a t-shirt is \$31.}

Explanation:

Since we have given that

The prices of three t-shirts styles  i.e $24, $30, $36 with their probability is given by

\frac{1}{6}, \frac{1}{2},\frac{1}{3}

As we know that,

E(X)= \sum_{1}^{3}x_iP(x_i)

\text{where} x_i \text{ is the prices of t- shirts styles}

Now,

x_1= \$24 , x_2=\$30 , x_3=$36

and

P(x_1)=\frac{1}{6},P(x_2)=\frac{1}{2}, P(x_3)=\frac{1}{3}

So,

E(X)= 24\times \frac{1}{6}+30\times\frac{1}{2}+36\times \frac{1}{3}\\=4+15+12\\=31

So, the expected value of a t-shirt = $31.

4 0
2 years ago
Loretta is trying to build the largest taco in the world . she use 2000 pound of ground beef one tenth as many pound of cheese a
Veseljchak [2.6K]
1/10 of 2000 is 200 pounds. so 200 pounds of cheese

i guess you mean 100 times more lettuce than beef so that would be 200,000 pounds of lettuce

200+200,000=200,200 final answer
3 0
2 years ago
Read 2 more answers
In ADEF, f = 610 inches, e = 590 inches and ZE=70°. Find all possible values of ZF,
Elina [12.6K]

Answer:

"76°" is the appropriate solution.

Step-by-step explanation:

Please find attachment of the diagram according to the given query.

The given values are:

In ΔDEF,

f = 610 inches

e = 590

∠E = 70°

∠F = ?

By using the law of sines, we get

⇒  \frac{Sin E}{e} =\frac{Sin  F}{f}

On substituting the values, we get

⇒  \frac{Sin70^{\circ}}{590} =\frac{SinF}{610}

On applying cross multiplication, we get

⇒   SinF=\frac{610\times Sin 70^{\circ}}{590}

On substituting the values, we get

⇒            =\frac{61\times 0.95969262}{59}

⇒            =\frac{57.3212499}{59}

⇒            =0.971546608

now,

⇒  F=Sin^{-1}(0.971546608)

⇒      =76^{\circ}

4 0
2 years ago
6. Matthew is planning to build a right triangular
saul85 [17]
The answer to this question will be B
8 0
2 years ago
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