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DENIUS [597]
2 years ago
7

8.9 – 1.4x + (–6.5x) + 3.4 simplify this expression

Mathematics
2 answers:
Monica [59]2 years ago
8 0

Answer:

12.3 - 7.9x

Step-by-step explanation:

I added the numbers without variables first then I added the numbers with variables:

8.9+3.4 = 12.3

-1.4x + -6.5x = -7.9x

MariettaO [177]2 years ago
4 0

Answer:

x = 1.6

Step-by-step explanation:

Simplify the expression

8.9 – 1.4x + (–6.5x) + 3.4

8.9 - 1.4x + (-6.5x) + 3.4

collect like terms

8.9 + 3.4 - 1.4x - 6.5x

12.3  - 7.9 x = 0

take 7.9x to the left side

12.3 = 7.9x

divide both sides by 7.9

x = 12.3/7.9

x = 1.55696202532

x = 1.6

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All members of our painting team paint at the same rate. If $20$ members can paint a $6000$ square foot wall in $24$ minutes, th
Yuri [45]

Let x represent time taken by 20 members to paint 9000 square foot wall.

We have been given that all members of our painting team paint at the same rate. 20 members can paint a 6000 square foot wall in 24 minutes. We are asked to find the time taken by 20 members to paint 9000 square foot wall.

We will use proportions to solve our given problem.

\frac{\text{Time taken}}{\text{Area of wall painted}}=\frac{24\text{ min}}{6000\text{ ft}^2}

\frac{x}{9000\text{ ft}^2}=\frac{24\text{ min}}{6000\text{ ft}^2}

\frac{x}{9000\text{ ft}^2}\times 9000\text{ ft}^2=\frac{24\text{ min}}{6000\text{ ft}^2}\times 9000\text{ ft}^2

x=\frac{24\text{ min}}{6}\times 9

x=4\text{ min}\times 9

x=36\text{ min}

Therefore, it will take 36 minutes for 20 members to paint 9000 square foot wall.

6 0
2 years ago
Read 2 more answers
Suppose that the ages of members in a large billiards league have a known standard deviation of σ = 12 σ=12sigma, equals, 12 yea
asambeis [7]

Answer:

n\geq 23

Step-by-step explanation:

-For a known standard deviation, the sample size for a desired margin of error is calculated using the formula:

n\geq (\frac{z\sigma}{ME})^2

Where:

  • \sigma is the standard deviation
  • ME is the desired margin of error.

We substitute our given values to calculate the sample size:

n\geq (\frac{z\sigma}{ME})^2\\\\\geq (\frac{1.96\times 12}{5})^2\\\\\geq 22.13\approx23

Hence, the smallest desired sample size is 23

3 0
2 years ago
In studying the insurance preferences of homeowners the following conclusions are made: A homeowner is three times as likely to
Ede4ka [16]

Answer:

0.632

Step-by-step explanation:

Given that a homeowner is three times as likely to purchase additional jewelry coverage as additional electronics coverage

If probability of purchasing additional electronics coverage = p, then prob of purchasing jewelry coverage = 3p

The two events are independent hence joint probability is product of these two.

i.e. P(both) = p(3p) =3p^2

This is given as 0.2

3p^2 =0.2\\p = 0.258

the probability that a homeowner purchases exactly one coverage.

=P(AUB)-P(A \bigcap B)

= Prob he purchases I + prob he purchases II-2(prob he purchases both)

= 0.258+3(0.258)-2(0.2)\\=0.632

5 0
2 years ago
HELP
kap26 [50]

Answer: Esy the answer is; C.

Step-by-step explanation:

The higher the negative value the less or lower the number is.

CONFUSING Right? XD

4 0
2 years ago
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The newest invention of the 6.431x staff is a three-sided die. On any roll of this die, the result is 1 with probability 1/2, 2
Gwar [14]

Answer:

<h2>The answer is 0.23(approx).</h2>

Step-by-step explanation:

The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.

We need to find the probability of getting exactly 3s as the result.

From the sequence of 6 independent rolls, 2 rolls can be chosen in ^6C_2 = \frac{6!}{2!\times4!} = \frac{30}{2} = 15 ways.

The probability of getting two 3 as outcome is \frac{1}{4} \times\frac{1}{4} = \frac{1}{16}.

In the rest of the 4 sequences, will not be any 3 as outcome.

Probability of not getting a outcome rather than 3 is 1 - \frac{1}{4} = \frac{3}{4}.

Hence, the required probability is 15\times\frac{1}{16}(\frac{3}{4})^4 = \frac{1215}{4096}≅0.2966 or, 0.23.

4 0
2 years ago
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