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bixtya [17]
2 years ago
8

Tristan wants to buy 12 cupcakes. Each cupcake costs $2.40. What is the best estimate for how much money Tristan should bring wi

th him to pay for cupcakes ?
Mathematics
2 answers:
Alenkasestr [34]2 years ago
4 0

Answer: $28.80

Step-by-step explanation:

AnnyKZ [126]2 years ago
4 0

Answer: $30.00

Step-by-step explanation:

Because of he wants to buy 12 and they cost 2.40 then you multiply both of the 12 ans 2.40 and you get 28.8. Round it up to 30.00.

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What is the sum of the polynomials? 1.3t3 + t2 – 42t + 8 1.3t3 + t2 – 6t + 8 1.9t3 + 8.4t2 – 42t 1.9t2 – 42t + 8
Aleksandr-060686 [28]
(1)1.3t^3 +t^2 -42t +8
(2)1.3t^3 + t^2 -6t +8
(3)1.9 t^3.+ 8.4^t^2 -42t
(4)1.9t^2 -42t + 8

I hope I got that right!!
okay, now they are all separated in columns, add the ones with the same powers (e.g (1)_ 1.3t^3 + (2) 1.3t^3 + (3) 1.9 t^3 = 4.5t^3.  

3 0
2 years ago
Read 2 more answers
If mJK=(7x-39) and mML)=87, find x
lilavasa [31]
If two chords of a circle are congruent, then their intercepted arcs are congruent
7x-39 = 87
7x = 87 + 39
7x = 126
x = 126/7
x = 18
5 0
2 years ago
The weight of people in a small town in missouri is known to be normally distributed with a mean of 154 pounds and a standard de
ad-work [718]
If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
The z-score for 173 pounds is given by:
z=\frac{173-154}{29}=0.655
Referring to a standard normal distribution table, and using z = 0.66, we find:
P(\bar x\ \textless \ 173)=0.7454
Therefore
P(\bar x\ \textgreater \ 173)=1-0.7454=0.2546
The answer is: 0.2546

4 0
2 years ago
Brett plays an acoustic guitar at an event for $500. At the end of the event, the sponsor tips him 20%. How much does Brett make
Blababa [14]
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8 0
2 years ago
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Find each measure for the given set of data: 11, 13, 17, 20, 22, 25, 27, 31, 31, 33, Mean= Median= Range= interquartile range= I
Tresset [83]

Answer:

Mean=23

Median =23.5

Range=22

Interquartile range = 14

Step-by-step explanation:

Given set of data

11,13,17,20,22,25,27,31,31,33

Mean =\frac{11+13+17+20+22+25+27+31+31+33}{10}

          =\frac{230}{10}

          =23

The(\frac{n}{2}) th term= the 5th term

                        =22

The  (\frac{n}{2}+1)^{th} term = The 6^{th term

                               = 25

The median = \frac{22+25}{2}

                   =23.5

Range = Highest term - lowest term

           =33- 11

            =22

Here lower half {11,13,17,20,22}

The middle number of lower half is first quartile.

Q₁ = 17

And lower half is{25,27,31,31,33}

The middle number of upper half is third quartile.

Q₃=31

Interquartile Range =Q₃-Q₁

                                =31-17

                                 =14

8 0
2 years ago
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