Answer:
The answer is below
Step-by-step explanation:
The question is not complete, what are the coordinates of point Q and R. But I would show how to solve this.
The location of a point O(x, y) which divides line segment AB in the ratio a:b with point A at (
) and B(
) is given by the formula:

If point Q is at (
) and S at (
) and R(x, y) divides QS in the ratio QR to RS is 3:5, The coordinates of R is:

Let us assume Q(−9,4) and S(7,−4)

To find perimeter you add up all the sides so the answer is 210
Answer:
Step-by-step explanation:
Water in a 10 gallon tank is draining at a rate of 2 gallons per hour.
= 10 - 2x
Water in a separate tank is filling at a rate of 4 gallons per hour.
= 10 + 4x
Equating both Equations together
10 - 2x = 10 + 4x
10 - 10 = 4x - 2x
How long until the tanks have the same amount of water?
Let the time = x
<span>The dimensions are 40 inches by 55 inches.
Explanation<span>:
We know that perimeter is the sum of all of the sides. Since this is rectangular, opposite sides are equal. This gives us
y+11/8y+y+11/8y=190.
Combining like terms, we have
2y+22/8y=190.
Writing 22/8 as a mixed number, we have
2y+2 3/4y=190
4 3/4y=190.
Divide both sides by 4 3/4:
(4 3/4y)</span></span>÷<span><span>(4 3/4)=190</span></span>÷<span><span>(4 3/4)
y=190</span></span>÷<span><span>(4 3/4).
Convert the mixed number to an improper fraction:
y=190</span></span>÷<span><span>(19/4).
To divide fractions, flip the second one and multiply:
y=190*(4/19)=760/19=40.
Since y=40, 11/8y=11/8(40)=440/8=55.</span></span>
You haven't provided the choices, therefore, I cannot provide an exact answer. However, I will help you with the concept.
For an order pair to be a solution to a system of equations, it has to satisfy <u>BOTH</u> equations. If it satisfies only one equation of the system or satisfy neither of the equations, the, it is not a solutions
<u><em>Examples:</em></u>
<u>System 1:</u>
x = y + 1
2x + 3y = 7
Let's check (2,1)
2 = 1 + 1 ........> equation 1 is satisfied
2(2) + 3(1) = 7 ......> equation 2 is satisfied
<u>(2,1) is a solution to this system</u>
<u>System 2:</u>
y = x + 3
y = x - 1
Let's check (2,1):
1 ≠ 2 + 3 ........> equation 1 isn't satisfied
1 = 2 - 1 ..........> equation 2 is satisfied
<u>(2,1) isn't a solution to this system</u>
<u>System 3:</u>
2y = 9 - 3x
3x + 2y = 9
Let's ceck (2,1):
2(1) ≠ 9 - 3(2) ..........> equation 1 isn't satisfied
3(2) + 2(1) ≠ 9 .........> equation 2 isn't satisfied
<u>(2,1) isn't a solution to this system
</u>
<u><em>Based on the above,</em></u> all you have to do is substitute with (2,1) in the system you have and pick the one where both equations are satisfied
Hope this helps :)