base 16y^2
height y^2 + y + 3
V = b*h
V = 16y^2(y^2 + y + 3)
V = 16y^4 + 16y^3 + 48y^2
Last option
Answer:
An alternative definition for the acceleration ax that can be written in terms of 
and 
is 
Step-by-step explanation:
We know that :
Now we are supposed to find an alternative definition for the acceleration ax that can be written in terms of and
So, We will use chain rule over here :
![a_x=\frac{dv_x}{dt}\\a_x=\frac{dv_x}{dt} \times \frac{dx}{dx}\\a_x=\frac{dv_x}{dx} \times \frac{dx}{dt}\\a_x=\frac{dv_x}{dx} \times \frac{dx}{dt} [\frac{dx}{dt}=v_x]\\a_x=\frac{dv_x}{dx} \times v_x\\a_x=v_x\frac{dv_x}{dx}](https://tex.z-dn.net/?f=a_x%3D%5Cfrac%7Bdv_x%7D%7Bdt%7D%5C%5Ca_x%3D%5Cfrac%7Bdv_x%7D%7Bdt%7D%20%5Ctimes%20%5Cfrac%7Bdx%7D%7Bdx%7D%5C%5Ca_x%3D%5Cfrac%7Bdv_x%7D%7Bdx%7D%20%5Ctimes%20%5Cfrac%7Bdx%7D%7Bdt%7D%5C%5Ca_x%3D%5Cfrac%7Bdv_x%7D%7Bdx%7D%20%5Ctimes%20%5Cfrac%7Bdx%7D%7Bdt%7D%20%20%5B%5Cfrac%7Bdx%7D%7Bdt%7D%3Dv_x%5D%5C%5Ca_x%3D%5Cfrac%7Bdv_x%7D%7Bdx%7D%20%5Ctimes%20v_x%5C%5Ca_x%3Dv_x%5Cfrac%7Bdv_x%7D%7Bdx%7D)
Hence an alternative definition for the acceleration ax that can be written in terms of and is
Answer: I'm pretty sure it would be -7º Celcius for it to be cancelled. Hope it helped!
Answer:
AB=2.775
BC=5.55
CA=6.475
Step-by-step explanation:
Since midpoints split their sides in half, we can see that the triangle MNK formed by the midpoints will be half the perimeter of the triangle ABC. Since P of MNK = 7.4, we know that the perimeter of ABC = 7.4 * 2, which is 14.8. Now we can split the 14.8 so that it follows the ratio.
3+6+7=16
14.8/16=0.925
AB=0.925*3=2.775
BC=0.925*6=5.55
CA=0.925*7=6.475
Answer:
Step-by-step explanation:
If DE = 4x+10,EF =2X -1, and DF= 9x - 15 find DF
(de + ef ) - df = 2e || 2e/2 = e || ed - e = d || ef - e = f || f + d = df
de + ef = 6x + 11 || (6x +11) - df = -3x -6 || 2e/2 = -3x/2 - 3 || (-3x/2 - 3) - de = x/2 + 7|| (- 3x/2 - 3) - ef = -x/2 - 1|| d + f = 6
