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marysya [2.9K]
2 years ago
13

Calculate the value of x to one decimal place. inches

Mathematics
1 answer:
kakasveta [241]2 years ago
5 0

Use the law of cosines: c^2=a^2+b^2-2ab\cos C

We have:

c=x\\a=3in\\b=7in\\C=54^o

substitute:

\cos54^o\approx0.5878\\\\c^2=3^2+7^2-2\cdot3\cdot7\cdot0.5878\\\\c^2=9+49-24.6876\\\\c^2=33.3129\to c=\sqrt{33.3129}\\\\c\approx5.8

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uysha [10]

Answer:

The perimeter of the trapezoid is 38.25\ units

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

so

In this problem

P=QR+RS+ST+QT

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

Q(8, 8), R(14, 16), S(20, 16),T(22, 8)

step 1

Find the distance QR

Q(8, 8), R(14, 16)

substitute the values in the formula

d=\sqrt{(16-8)^{2}+(14-8)^{2}}

d=\sqrt{(8)^{2}+(6)^{2}}

d=\sqrt{100}

QR=10\ units

step 2

Find the distance RS

R(14, 16), S(20, 16)

substitute the values in the formula

d=\sqrt{(16-16)^{2}+(20-14)^{2}}

d=\sqrt{(0)^{2}+(6)^{2}}

d=\sqrt{36}

RS=6\ units

step 3

Find the distance ST

S(20, 16),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-16)^{2}+(22-20)^{2}}

d=\sqrt{(-8)^{2}+(2)^{2}}

d=\sqrt{68}

ST=8.25\ units

step 4

Find the distance QT

Q(8, 8),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-8)^{2}+(22-8)^{2}}

d=\sqrt{(0)^{2}+(14)^{2}}

d=\sqrt{196}

QT=14\ units

step 5

Find the perimeter

P=10+6+8.25+14=38.25\ units

6 0
2 years ago
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MissTica
326 = 12m + 6c + x = 18 rounded to 19
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Answer:

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Step-by-step explanation:

given:

s=301/2

t=2/3

we have,

v=s/t

v=(301/2)/(2/3)

=(301/2)×3/2

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v=225.75

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Answer:

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Answer:

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The amount of soup the can will hold is equal to the volume of the can.

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The amount of soup the can will hold is;

50π inches cubed = 157.08 inches cubed

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