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Svetlanka [38]
2 years ago
14

Complete the point-slope equation of the line through (8,-8)(8,−8)left parenthesis, 8, comma, minus, 8, right parenthesis and (9

,8)(9,8)left parenthesis, 9, comma, 8, right parenthesis.
Mathematics
1 answer:
yarga [219]2 years ago
3 0

Answer:

Point-slope equation of line is given by:

y-8=16(x-9)

Step-by-step explanation:

Given points:

(8,-8)\ and\ (9,8)

Point-slope equation of line is given by:

y-y_1=m(x-x_1)

Where (x_1,y_1) is a point on the line and m is slope of line.

Slope of line m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{8-(-8)}{9-8}

m=\frac{8+8}{1}

m=16

Using point (9,8) and slope m=16  point-slope equation of line is given by:

y-8=16(x-9)

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What is the sum of the distinct prime factors of 315
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Answer: The exponents in the prime factorization are 2, 1, and 1. Adding one to each and multiplying we get (2 + 1)(1 + 1)(1 + 1) = 3 x 2 x 2 = 12. Therefore 315 has exactly 12 factors.

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7 0
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Determine Which Number in the set below that are integers ???? {-15, 24 ,5/8 , 4.5, -6.25} A) {-15, 24} B) {-15, 24 ,5/8, 4.5, -
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7 0
1 year ago
Himpunan penyelesaian pertidaksamaan nilai mutlak |2x-4| &gt; |3x+2|
Stells [14]

Answer:

The solution in interval notation is:

(-6,\frac{2}{5}).

The solution in inequality notation is:

-6.

Step-by-step explanation:

I think you are asking how to solve this for x.

Keep in mind |x|=\sqrt{x^2}.

|2x-4|>|3x+2|

\sqrt{(2x-4)^2}>\sqrt{(3x+2)^2}

If \sqrt{u}>\sqrt{v} then u>v.

(2x-4)^2>(3x+2)^2

Subtract (2x-4)^2 on both sides:

0>(3x+2)^2-(2x-4)^2

Factor the difference of squares a^2-b^2=(a-b)(a+b):

0>((3x+2)-(2x-4))((3x+2)+(2x-4))

Simplify inside the factors:

0>(x+6)(5x-2)

(x+6)(5x-2)

The left hand side is a parabola that faces up.  I know this because the degree is 2.  

The zeros of the the parabola are at x=-6 and x=2/5.

We can solve x+6=0 and 5x-2=0 to reach that conclusion.

x+6=0

Subtract 6 on both sides:

x=-6

5x-2=0

Add 2 on both sides:

5x=2

Divide both sides by 5:

x=2/5

Since the parabola faces us and (x+6)(5x-2) then we are looking at the interval from x=-6 to x=2/5 as our solution.  That part is where the parabola is below the x-axis.  We are looking for where it is below since it says the where is the parabola<0.

The solution in interval notation is:

(-6,\frac{2}{5}).

The solution in inequality notation is:

-6.

6 0
2 years ago
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