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konstantin123 [22]
2 years ago
10

2. A student on the track team runs 45 minutes each day as a part of her training. She

Mathematics
1 answer:
fomenos2 years ago
8 0

Answer:

D

Step-by-step explanation:

The basic equation to solve this would be D = RT, which is

D is Distance

R is Rate (speed)

T is time

To find total distance D, we can find individual distances for two legs of the whole.

First Leg:

R = 8

T = a

D = 8a

Second Leg:

R = 7.5

T = b

D = 7.5b

Total distance D is:

D = 8a + 7.5b

Moreover, we know student runs 45 minutes in total hence a + b = 45 or we can say a = 45 - b, so we can replace this in the equation found:

D = 8a + 7.5b

D = 8(45 - b) + 7.5b

Answer choice D is right.

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a sports statistician claim that the mean winning times for boston marathon women's open division champions is at least 2.68 hou
GenaCL600 [577]

Answer:

We conclude that the mean winning times for Boston marathon women's open division champions is at least 2.68 hours.

Step-by-step explanation:

We are given that a sports statistician claim that the mean winning times for Boston marathon women's open division champions is at least 2.68 hours.

The mean winning time of a sample of 30 randomly selected Boston marathon women's open division champions is 2.60 hours. assume the population standard deviation is 0.32 hours.

<em>Let </em>\mu<em> = </em><u><em>mean winning times for Boston marathon women's open division champions.</em></u>

So, Null Hypothesis, H_0 : \mu\geq 2.68 hours      {means that the mean winning times for Boston marathon women's open division champions is at least 2.68 hours}

Alternate Hypothesis, H_A : p < 2.68 hours      {means that the mean winning times for Boston marathon women's open division champions is less than 2.68 hours}

The test statistics that would be used here <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                        T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean winning time = 2.60 hours

            \sigma = population standard deviation = 0.32 hours

            n = sample of women's open division champions = 30

So, <em><u>test statistics</u></em>  =   \frac{2.60-2.68}{\frac{0.32}{\sqrt{30} } }

                               =  -1.37

The value of z test statistics is -1.37.

Now, P-value of the test statistics is given by following formula;

         P-value = P(Z < -1.37) = 1 - P(Z \leq 1.37)

                       = 1 - 0.9147 = <u>0.0853</u>

Since, P-value of the test statistics is more than the level of significance as 0.0853 > 0.05, so <u>we have insufficient evidence to reject our null hypothesis</u> as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean winning times for Boston marathon women's open division champions is at least 2.68 hours.

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