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AnnZ [28]
2 years ago
14

A program that was intended to cure a person’s fear of spiders was offered at a local zoo. Volunteers with a fear of spiders par

ticipated in the program, which included holding a spider for 15 minutes. One month after they completed the program, the participants were contacted and surveyed about the program. Over 90 percent of the participants claimed they were cured of their fear of spiders. Based on the description of the program, which of the following statements is true?
(A) Because over 90% of the participants claimed to be cured, the results prove that holding a spider will cure a person's fear of spiders
(B) Because over 90% of the participants claimed to be cured, the results can be generalized to the population of all people who have a fear of spiders.
(C)Because the participants were volunteers, the study is a census of all people in the local area who have a fear of spiders. confounding variable and the results can be generalized to the population of all people who have a a fear of spider
(D)Because the participants were self-selected, a person's desire to be cured could be a confounding variable.
(E) Because participants held a spider for 15 minutes, the study is an experiment fear of spiders.
Mathematics
1 answer:
fiasKO [112]2 years ago
5 0

Answer:

Option E

Step-by-step explanation:

The volunteers held spider for 15 minutes

90% of participants confessed that they were cured from the fear of spider

The available statement describes the 90% of the participants claimed they were cured of their fear of spiders. The statement also states that the participants held spider for 15 minutes only. These two parameters are only combined in one answer, option E which captures both. Therefore, we can rightfully conclude that the results can be generalized to the population of all people who have a fear of spiders.

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12/23 = probability first is a girl
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probability of both 132/506
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2 years ago
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The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t2 where d equals the
igomit [66]

Answer:

The rate of change determines the average speed of the ball when it is dropped from the building.

Step-by-step explanation:

d(t) = 16t^2

when t = 2

d(t) = 16 (2)²

d(t) = 64

when t = 5

d(t) = 16 (5)²

d(t) = 400

Average speed/rate of change = distance/time = 64/2 = 32 feet

Average speed/rate of change = distance/time = 400/5 = 80 feet

The rate of change determines the average speed of the ball when it is dropped from the building.

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It costs 20 cents to receive a photo and 30 cents to send a photo from a cellphone. C is the cost of one photo (either sent or r
ddd [48]

Answer:

(a) PC(C)=     \left \{ {{0.6 \ \ \ \ x=20} \atop 0.4 \ \ \ \ {x=30}} \right. \\\ 0 \ \ \ \ \ \ \ else

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Step-by-step explanation:

Given:

Cost to receive a photo = 20 cents

Cost to send a photo = 30 cents

Probability of receiving a photo = 0.6

Probability of sending a photo = 0.4

We need to find

(a) PC(c)

(b) E[C]

Solution:

(a)

PC(C)=     \left \{ {{0.6 \ \ \ \ c=20} \atop 0.4 \ \ \ \ {c=30}} \right. \\\ 0 \ \ \ \ \ \ \ else

(b)

Expected value can be calculated by multiplying probability with cost.

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OverLord2011 [107]

Answer:

60 i think

Step-by-step explanation:

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Marta_Voda [28]

Answer:

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Step-by-step explanation:

A rope that is 5814 meters long needs to be cut into 27 sections

The number of 27 meter sections of rope that can be created can be calculated by dividing 5814 by 27

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