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saveliy_v [14]
2 years ago
10

The student government wants to determine the theme for the eighth grade dance. Which group would it be best to take a sample fr

om?
Mathematics
2 answers:
Serga [27]2 years ago
7 0
To ask the 8th graders
Juliette [100K]2 years ago
5 0
The best group to take a sample from would be the eighth graders because they are the ones who will be participating in the dance, so they should have the most input.
You might be interested in
If A is the center of the circle, then which statement explains how segment EF is related to segment GF? Circle A with inscribed
Brrunno [24]

Answer:

segment EF ≅ segment GF because both segments are the same distance from the center of circle A ⇒ answer B

Step-by-step explanation:

* Lets revise some facts in the circle

- The perpendicular segment from the center of the circle to a chord

 bisects it

- A segment from the center of a circle to the midpoint of a cord is

 perpendicular to it

- Congruent chords in a circle are equidistant from the center of the circle,

 that means the perpendicular distances from the center of the circle

 to the chords are equal

- If two chords in a circle are equidistant from the center of the circle

 <em>( the perpendicular distances from the center of the circle to the </em>

<em>   chords are equal) </em>, then they are congruent

* Lets solve the problem

∵ ∠EDA is right angle

∵ AD ⊥ FE

∵ ∠GHA is right angle

∵ AH ⊥ FG

∵ AD = AH

∵ EF and GF are chords in the circle A

∴ The chords EF and GF are equidistant from the center of the circle A

- By using the bold fact above

∴ EF ≅ GF

* segment EF ≅ segment GF because both segments are the same

 distance from the center of circle A

5 0
2 years ago
A leasing agent makes $23 an hour for the first 10 hours he works during a
skelet666 [1.2K]

Answer:

I believe the answer is A

Step-by-step explanation:

3 0
2 years ago
YOU DONT HAVE TO DO ALL IF YOU DONT WANT TO JUST DO WHAT YOU CAN
Vikki [24]

Answer:

(Warning) Not sure this is completley correct but this is just what I did.

Part A

Does the data for Amit’s puppy show a function? Why or why not?

It does show a function because it passes the vertical line test (no two points have the same x value).

Part B

Is the relationship for Amit’s puppy’s weight in terms of time linear or nonlinear? Explain your response.

Nonlinear because the line isn’t straight

Part C

Is the relationship between Amit’s puppy’s weight in terms of time increasing or decreasing? Explain your response.

Increasing because it is gaining weight

Part D

Does the data for Camille’s puppy show a function? Why or why not?

Yes, it does, because each input value has a unique output value

Part E

Is the relationship for Camille’s puppy’s weight in terms of time linear or nonlinear? Explain your response.

It is a linear function because the line has no curve, and the line is constant.

Part F

Is the relationship between Camille’s puppy’s weight in terms of time increasing or decreasing? Explain your response.

Increasing because as the puppy gets older it gains weight.

Part G

Does the data for Olivia’s puppy show a function? Why or why not?

Yes, it does, because each input value has a unique output value. The graph attached ( which shows the data for Camille’s puppy), that each x-value (Weeks) has a unique y-value (Weight in pounds).

Therefore, based on this and keeping in mind the explanation before, you can conclude that the data for Camille’s puppy shows a function.

Part H

Is the relationship for Olivia’s puppy’s weight in terms of time linear or nonlinear? Explain your response

Yes, it linear because it’s a straight line.

Part I

Is the relationship for Olivia’s puppy’s weight in terms of time increasing or decreasing? Explain your response. Increasing. For every week that goes by, Olivia's puppy is gaining one pound. 6-5= 1  14-13= 1. Gaining a pound every week makes the puppy’s weight increase.

Part J

Which two relationships have a y-intercept and a constant rate of change?

They all have y-intercepts and only Olivia and camilles have a constant rate of change.

Part A

To compare the linear functions, you first need to find their equations. For each of the linear functions, write an equation to represent the puppy’s weight in terms of the number of weeks since the person got the puppy.

Linear equation, y=mx+b

Exponential equation, y=a(b)×

Part B

Now you can compare the functions. In each equation, what do the slope and y-intercept represent in terms of the situation?

The y-intercept in the situation is 2/6.

Part C

Whose puppy weighed the most when the person got it? How much did it weigh?

Olivia’s puppy, it weighed 5 pounds

Part D

Whose puppy gained weight the slowest? How much did it gain per week?

Olivia’s puppy gained weight the slowest because it started off with more weight but only gained around 1 pound every week.

Part E

You can also graph the functions to compare them. Using the Edmentum Graphing Tool, graph the two linear functions. Paste a screenshot of the two functions in the space provided. How could you find which puppy had a greater initial weight from the graph? How could you find which puppy gained weight the slowest?

The edmentum graphing tool is opening up I tried it more than once but, the linear graphs would be Camille puppy and olivia's. And I could tell which one had a greater weight by how much they had at week 1 and how much they gained the weeks later. I could find which puppy gained weight the slowest by looking at the weight gained and graphed.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
The shuttle bus from your parking lot and your office building operates on a 15 minute schedule. You arrive at the parking lot a
mylen [45]

Answer:

(a) The standard deviation of your waiting time is 4.33 minutes.

(b) The probability that you will have to wait more than 2 standard deviations is 0.4227.

Step-by-step explanation:

Let <em>X</em> = the waiting time for the bus at the parking lot.

The random variable <em>X</em> is uniformly distributed with parameters <em>a</em> = 0 to <em>b</em> = 15.

The probability density function of <em>X</em> is given as follows:

f_{X}(x)=\frac{1}{b-a};\ a

(a)

The standard deviation of a Uniformly distributed random variable is given by:

SD=\sqrt{\frac{(b-a)^{2}}{12}}

Compute the standard deviation of the random variable <em>X</em> as follows:

SD=\sqrt{\frac{(b-a)^{2}}{12}}

      =\sqrt{\frac{(15-0)^{2}}{12}}

      =\sqrt{\frac{225}{12}}

      =\sqrt{18.75}\\=4.33

Thus, the standard deviation of your waiting time is 4.33 minutes.

(b)

The value representing 2 standard deviations is:

X=2\times SD=2\times4.33=8.66

Compute the value of P (X > 8.66) as follows:

P(X>8.66)=\int\limits^{10}_{8.66} {\frac{1}{15-0}}\, dx\\

                    =\frac{1}{15}\times \int\limits^{10}_{8.66} {1}\, dx\\

                    =\frac{1}{15}\times |x|^{15}_{8.66}\\

                    =\frac{15-8.66}{15}\\

                    =0.4227

Thus, the probability that you will have to wait more than 2 standard deviations is 0.4227.

4 0
2 years ago
An aquarium with a square base has no top. There is a metal frame. Glass costs 5 dollars/m2 and the frame costs 2 dollars/m. The
adell [148]

Answer:

C = 420/h + 400

Step-by-step explanation:

Let s be the side of the square base.

Let h be the height

Volume = s*h

20 = s*h

s = 20/h

Cost of glass is

5(20/h) + 5(4* h*20/h)

= 100/h + 400

Cost of frame is

2*4(20/h) + 2*4(20/h)

= 160/h + 160/h

= 320/h

Total cost = C

C = cost of glass + cost of frame

C = 100/h + 400 + 320/h

C = 420/h + 400

3 0
2 years ago
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