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wlad13 [49]
2 years ago
5

Which function represents g(x), a reflection of f(x) = Two-fifths (10)x across the x-axis? g(x) = Negative two-fifths(10)x g(x)

= Negative two-fifths (one-tenth) Superscript x g(x) = Two-fifths (one-tenth) Superscript negative x g(x) = Two-fifths(10)-x
Mathematics
1 answer:
erastova [34]2 years ago
7 0

Answer:

The correct option is;

g(x) = Negative two-fifths(10)x

Step-by-step explanation:

The rule for the reflection across the x-axis is as follows;

Reflection about the x-axis

Pre-image point before reflection = (x, y)

Point of image after reflection = ((x, -y)

Therefore, the x coordinate remains the same while the y coordinate changes sign

For which given that f(x) = y = 2/5(10)x and g(x) = Reflection of f(x) across the x-axis, we have

Reflection about the x-axis

Pre-image point before reflection = (x, f(x))

Point of image after reflection = (x, g(x))

Hence g(x) = -f(x) = -2/5(10)x.

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uysha [10]

Answer:

The perimeter of the trapezoid is 38.25\ units

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

so

In this problem

P=QR+RS+ST+QT

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

Q(8, 8), R(14, 16), S(20, 16),T(22, 8)

step 1

Find the distance QR

Q(8, 8), R(14, 16)

substitute the values in the formula

d=\sqrt{(16-8)^{2}+(14-8)^{2}}

d=\sqrt{(8)^{2}+(6)^{2}}

d=\sqrt{100}

QR=10\ units

step 2

Find the distance RS

R(14, 16), S(20, 16)

substitute the values in the formula

d=\sqrt{(16-16)^{2}+(20-14)^{2}}

d=\sqrt{(0)^{2}+(6)^{2}}

d=\sqrt{36}

RS=6\ units

step 3

Find the distance ST

S(20, 16),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-16)^{2}+(22-20)^{2}}

d=\sqrt{(-8)^{2}+(2)^{2}}

d=\sqrt{68}

ST=8.25\ units

step 4

Find the distance QT

Q(8, 8),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-8)^{2}+(22-8)^{2}}

d=\sqrt{(0)^{2}+(14)^{2}}

d=\sqrt{196}

QT=14\ units

step 5

Find the perimeter

P=10+6+8.25+14=38.25\ units

6 0
2 years ago
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Jackson buys a grape snow cone on a hot day. By the time he eats all the "snow" off the top, the paper cone is filled with 27\pi
anyanavicka [17]

Question:

Jackson buys a grape snow cone on a hot day. By the time he eats all the "snow" off the top, the paper cone is filled with 27\pi27π27, pi cm^3 3 start superscript, 3, end superscript of melted purple liquid. The radius of the cone is 333 cm. What is the height of the cone?

Answer:

The height of the cone is 9 \ cm

Explanation:

It is given that the radius of the cone is 3 \ cm

The volume of the cone is 27\pi

The height of the cone can be determine using the formula,  

$V=\frac{1}{3} \pi r^{2} h$

Substituting the values V=27 \pi and r=3, we get,

$27 \pi=\frac{1}{3} \pi(3)^{2} h$

Multiplying both sides by 3, we have,

$81 \pi= 9\pi h$

Dividing both sides by $9 \pi$, we have,

9=h

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4 0
2 years ago
Emily collected $950 selling Girl Scout cookies all day Saturday. Emily's troop collected 10 times as much as she did. How much
LuckyWell [14K]
Since the troop made 10 times her then you multiply 950 by 10 and that will give you 9510
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marshall27 [118]

Answer:

The answer to your question is 2184

Step-by-step explanation:

Data

Equation    P(x) = 0.68x² - 0.048x + 1

x = years

population = 33984

Process

1.- Substitute the population in the equation

                   33984 = 0.84x² - 0.048x + 1

2.- Equal to zero

                   0.84x² - 0.048x + 1 - 33984 = 0

3.- Simplify

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4.- Solve for x

x = \frac{0.048 +- \sqrt{(0.048^{2}) - (4)(0.84)(-33982)}}{2(0.84)}

x = \frac{0.048 +- \sqrt{337.9}}{1.68}

x1 = 201.2

x2 = -201.2

Only x1 is correct because time can not be negative

5.- Calculate the year

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vodomira [7]

Answer:

Step-by-step explanation:

65

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