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a_sh-v [17]
2 years ago
5

This​ year, druehl,​ inc., will produce 57 comma 60057,600 hot water heaters at its plant in​ delaware, in order to meet expecte

d global demand. to accomplish​ this, each laborer at the plant will work 200200 hours per month. if the labor productivity at the plant is 0.250.25 hot water heaters per labor​ hour, how many laborers are employed at the​ plant?
Mathematics
1 answer:
ivolga24 [154]2 years ago
5 0
If one labour works 200 hours per month, the amount of hot water heaters the labour can produce is = 200 × 0.25 = 50 hot water heaters

The demand is to produce 57600 hot water heaters

The number of labourers employed is 57600 ÷ 50 = 1152 labourers
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Graph y ≥ -x^2 - 1. Click on the graph until the correct graph appears.
Nitella [24]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

y\geq -x^{2}-1

The solution of the inequality is the shaded area above the solid line of the equation of the  parabola y= -x^{2}-1

The vertex of the parabola is the point (0,-1)

The parabola open downward (vertex is a maximum)

using a graphing tool

see the attached figure

6 0
2 years ago
Which equation is y = 3(x – 2)2 – (x – 5)2 rewritten in vertex form? Y = 3 (x minus seven-halves) squared minus StartFraction 27
densk [106]

Answer: y = 2 (x minus one-half) squared minus StartFraction 27 Over 2 EndFraction

or

y=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}

Step-by-step explanation:

Vertex form of equation : f (x) = a(x - h)^2 + k,where (h, k) is the vertex of the parabola.

y=3(x-2)^2-(x-5)^2\\\\=3(x^2+4-4x)-(x^2+25-10x)\\\\=3x^2+12-12x-x^2-25+10x\\\\=2x^2-2x-13\\\\=2(x^2-x-\dfrac{13}{2})\\\\=2(x^2-x+\dfrac{1}{4}-\dfrac{1}{4}-\dfrac{13}{2})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{1+26}{4})\\\\=2((x-\dfrac{1}{2})^2-\dfrac{27}{4})=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}

Hence, the vertex form of the equation is y=2((x-\dfrac{1}{2})^2)-\dfrac{27}{2}

8 0
2 years ago
Read 2 more answers
Liam had \$250$250dollar sign, 250. Then, he and his classmates bought a present for their teacher, evenly splitting the \$p$pdo
Nostrana [21]

Answer: 250- 9/24

p

​

250, minus, start fraction, p, divided by, 24, end fraction dollars left.

Step-by-step explanation:

Liam had \$250$250dollar sign, 250. Then, he and his classmates bought a present for their teacher, evenly splitting the \$p$pdollar sign, p cost among the 242424 of them.                                                                                                                  

3 0
2 years ago
Susan is going to rent a truck for one day. There are two companies she can choose from, and they have the following prices. Com
hoa [83]

Idk if this is correct but ugh ill try my best

B = 55 + .6x

65 = 55 + .6x

subtract 55 from each side

10 = .6x

Multiply each side by .6 =

6 = x or in this case m

A charges les than B when m > 6

tell me if I'm wrong if I am


4 0
2 years ago
Sketch the region of integration for the following integral. ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ
solong [7]

Answer:

The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

Step-by-step explanation:

We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line  x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.    

3 0
2 years ago
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