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a_sh-v [17]
2 years ago
5

This​ year, druehl,​ inc., will produce 57 comma 60057,600 hot water heaters at its plant in​ delaware, in order to meet expecte

d global demand. to accomplish​ this, each laborer at the plant will work 200200 hours per month. if the labor productivity at the plant is 0.250.25 hot water heaters per labor​ hour, how many laborers are employed at the​ plant?
Mathematics
1 answer:
ivolga24 [154]2 years ago
5 0
If one labour works 200 hours per month, the amount of hot water heaters the labour can produce is = 200 × 0.25 = 50 hot water heaters

The demand is to produce 57600 hot water heaters

The number of labourers employed is 57600 ÷ 50 = 1152 labourers
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Dylan scored a total of 48 points in first 4 games of the basketball season. Which equation can be used to find g, the average n
belka [17]
G= 48/4???? that would make sense wouldn't it? because 48/4 would be the total number of points divided by the amount of games in which those points are scored. 

3 0
1 year ago
Read 2 more answers
Express x in term of y:x/7+2y=6​
lions [1.4K]

Answer:

You have to multiply the denorminator to both sides in order to make x the subject :

\frac{x}{7 + 2y}  = 6

x = 6(7 + 2y)

8 0
1 year ago
points P and Q lie 240 m apart in line with and on opposite sides of a communications tower. the angles of elevation to the top
Leona [35]

Answer:

The height of the tower is 130.5m

Step-by-step explanation:

In the question, we are given the following values:

The angles of elevation to the top of the tower from P = 50°

The angles of elevation to the top of the tower from Q = 45°

The angles of elevation to the top of the tower from P = 50°

Hence,cot P = 1/ tan(50°)

The angles of elevation to the top of the tower from Q = 45°

Hence, tan 45° = 1

In the question,we are told Points P and Q lie 240 m apart in line with and on opposite sides of a communications tower.

Therefore,

PQ = height of the tower( tan Q + 1/tan P)

240m = height of the tower( tan 45° + 1/ tan 50°)

240m = h(1 + 1/tan 50°)

h = (240 m)/(1 + 1/tan (50°))

h = 130.49863962 meters

Therefore, the height of the tower to the nearest tenth of a meter is 130.5 meters(m)

5 0
2 years ago
Triangle N T M is shown. Angle N T M is a right angle. An altitude is drawn from point T to point U on side N M to form a right
stich3 [128]

Answer:

The value of y is 6\sqrt{3} units ⇒ 2nd answer

Step-by-step explanation:

In the attached figure

∵ ∠MTN is a right angle

∵ TU is the altitude of the triangle

- There are some rules in this triangle let us revise them

  • (NT)² = NU . NM
  • (MT)² = MU . MN
  • (TU)² = MU . NU
  • TM . TN = TU . MN

∵ NU = 9 units

∵ UM = 3 units

∵ MN = UM + NU

∴ MN = 3 + 9 = 12 units

- By using the 1st rule above

∴ (NT)² = 9 × 12

∴ (NT)² = 108

- Take a square root to both sides

∴ NT = \sqrt{108}

- Simplify the root

∴ NT = 6\sqrt{3} units

∵ NT is y

∴ y = 6\sqrt{3} units

The value of y is 6\sqrt{3} units

8 0
2 years ago
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Evaluate the integral. 17 sin2(x) cos3(x) dx step 1 since 17 sin2(x) cos3(x) dx has an odd power of of cos(x), we will convert a
lord [1]
To evaluate 17 int (sin^2 (x)  cos^3(x))
From Trig identity. Cos^2(x) + sin^2(x) =1. Cos^2(x) = 1 - sin^2 (x) 
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Let u = sinx then du = cosxdx
Substituting into (1) we have
int (u^2du) - int (u^4du)
u^3/3 - u^5/5
Substitute value for u we have 
(sinx)^3/3 - (sinx)^5/5
Hence we have 17 [ sin^3x/3 - sin^5x/5]
7 0
1 year ago
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