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hichkok12 [17]
2 years ago
8

On a track and field team, 8% of the members run only long-distance, 32% compete only in field events, and 12% are sprinters onl

y. Find the probability that a randomly chosen team member runs only long-distance or competes only in field events.
​
Mathematics
1 answer:
kondor19780726 [428]2 years ago
7 0

Answer:

0.40

Step-by-step explanation:

Members who run only  long distance = 8%

So, probability that a member will run only long distance = P(A) = 0.08

Members who compete only in field events = 32%

So, probability that a member will compete only in field events = P(B) 0.32

Members who are sprinters = 12%

So, probability that a member is sprinter = P(C) 0.12

We have to calculate the probability that a randomly chosen team member runs only long-distance or competes only in field events. i.e we have to find P(A or B). Since these events cannot occur at the same time, we can write:

P(A or B) = P(A) + P(B)

Using the values, we get:

P(A or B) = 0.08 + 0.32 = 0.40

Thus, the probability that a randomly chosen team member runs only long-distance or competes only in field events is 0.40

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klemol [59]

Answer:

We accept the null hypothesis.    

Step-by-step explanation:

We are given the following in the question:

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We fail to reject the null hypothesis and accept it.

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2 years ago
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BlackZzzverrR [31]

Answer:

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Step-by-step explanation:

Had Obi spent only ?12, they would have been even. Thus ?12 is the same as 5-2 = 3 "ratio units". So, each "ratio unit" is worth ?12/3 = ?4.

Then Obi started the day with 5·4 = 20, and Obi started the day with 2·4 = 8. Obi ended with 0, which is 8 less than Rudy.

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