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german
2 years ago
6

Simplify: StartRoot 64 r Superscript 8 Baseline EndRoot

Mathematics
1 answer:
patriot [66]2 years ago
5 0

Answer:

  8r^4

Step-by-step explanation:

  \sqrt{64r^8} =\sqrt{(8r^4)^2}=\boxed{8r^4}

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A meteorologist is studying the monthly rainfall in a section of the Brazilian rainforest. She recorded the monthly rainfall, in
aleksandr82 [10.1K]

Answer:

12.405

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Please... Solve this: the bearing of a tree from a house is 295°. Find the bearing of the house from the tree.
jonny [76]

Given parameters:

Bearing of the tree from the house  = 295°

Unknown:

Bearing of the house from the tree = ?

Solution:

This is whole circle bearing problem(wcb). There are different ways of representing directions from one place to another. In whole circle bearing, the value of the bearing varies from 0° to 360° in the clockwise direction.

To find the back bearing in this regard, simple deduct the forward bearing from 360°;

    Backward bearing  = 360° -295°

                                    = 65°

The bearing from house to the tree is 65°

4 0
2 years ago
381.10-214.43 equals
dmitriy555 [2]

Answer:

166.67

Step-by-step explanation:

3 0
2 years ago
Imaginá que tenés 125 dados cúbicos del mismo tamaño ¿Cuantos dados de altura tiene el cubo de mayor tamaño que podés armar apil
kumpel [21]

Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

V = L^{3}

Donde:

L - Longitud de la arista, medida en dados.

V - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

L = \sqrt[3]{V}

Dado que V = 125\,dados^{3}, encontramos que la altura del cubo de mayor tamaño sería:

L =\sqrt[3]{125\,dados^{3}}

L = 5\,dados

Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) El área cuadrada formada por cubos está determinada por la siguiente fórmula:

A = L^{2}

Donde:

L - Longitud de arista, medida en dados.

A - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de L tal que no supere 125 y de un área entera. Es decir:

L \leq 125\,dados

Si cada cubo tiene un área de 1 dado cuadrado, entonces un cuadrado conformado por 125 dados tiene un área total de 125 dados cuadrados. Entonces:

L^{2}< 125\,dados^{2}

Esto nos lleva a decir que:

L < 11.180\,dados

Entonces, la longitud máxima del cuadrado con la mayor cantidad de cubos posible es de 11 dados. El número total requerido de cubos es el cuadrado de esa cifra, es decir:

n = (11\,dados)^{2}

n = 121\,dados

Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

4 0
2 years ago
If ray NP bisects &lt;MNQ, m&lt;MNQ=(8x+12)°, m&lt;PNQ=78°, and m&lt;RNM=(3y-9)°, find the value of x and y
aksik [14]

Step 1

<u>Find the measure of angle x</u>

we know that

If ray NP bisects <MNQ

then

m<MNQ=m<PNM+m<PNQ ------> equation A

and

m<PNM=m<PNQ -------> equation B

we have that

m<MNQ=(8x+12)°

m<PNQ=78°

so

substitute in equation A

(8x+12)=78+78-------> 8x+12=156------> 8x=156-12

8x=144------> x=18°

Step 2

<u>Find the measure of angle y</u>

we have

m<PNM=(3y-9)°

m<PNM=78°

so

3y-9=78------> 3y=87------> y=29°

therefore

<u>the answer is</u>

the measure of x is 18° and the measure of y is 29°


7 0
2 years ago
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