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aniked [119]
2 years ago
10

Please help i don’t know how to do this

Mathematics
1 answer:
stich3 [128]2 years ago
5 0
Good luck with that man
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xxTIMURxx [149]

Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

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1 year ago
What is the point of intersection when the system of equations below is graphed on the coordinate plane? (1, –3) (–1, 3) (1, 3)
Ainat [17]

( - 1 - 3)
it's lower
5 0
1 year ago
Read 2 more answers
I need help please help me
Lostsunrise [7]

Answer:

which one do you need help on

6 0
2 years ago
On september 8, 2004, the genesis spacecraft crashed in the utah desert because its parachute did not open. the 210-kg capsule h
maw [93]
311km/h = 86.389 m/s 
<span>Initial KE </span>
<span>= 0.5 * 210 * 86.389^2 J </span>

<span>work done by force of ground </span>
<span>= F * 0.81 J </span>

<span>0.5 * 210 * 86.389^2 = 0.81 F </span>

<span>F = 967433.58 N </span>

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2 years ago
In an article in Statistics and Computing [""An Iterative Monte Carlo Method for Nonconjugate Bayesian Analysis"" (1991, pp. 119
Marina CMI [18]

Answer:

Step-by-step explanation:

Hello!

a)

The dependent variable is

Y: length of a dugong

The explanatory variable is

X: age of a dugong

You need to estimate the linear regression of the length of the dugongs as a function of their age.

Using the given data I've estimated the regression using a statistic software:

The regression model is E(Yi)= α + βXi

The estimated model is ^Yi= a + bXi

Where a is the estimate of the intercept and b is the estimate of the slope:

a= 2.02

b= 0.03

And the estimate of the population variance of the error is Se²= 0.03

The estimated regression equation is ^Yi= 2.02 + 0.03Xi

b)

You have to estimate the length of a dugong when its age is 11 years using the model, for this all you have to do is replace X=11 in the regression line and calculate the corresponding ^Y value:

^Yi= 2.02 + 0.03*11= 2.35

The average length of an 11-year-old dugong should be 2.35.

I hope it helps!

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2 years ago
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