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romanna [79]
2 years ago
5

Carlton Hinkler offered $179,900 for a home that had been priced at $210,500. The seller agreed to the offer. If he made a $36,0

00
down payment, what is the mortgage loan amount?
Mathematics
1 answer:
katovenus [111]2 years ago
5 0

Answer

The answer will be 66600

P.S i hope i'm right i am only in 5th grade and i do not know if this is adding and subtracting

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40

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Juanita wants to perform row operations on the augmented matrix for the system below (See pictures). Which matrix should Juanita
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Answer:

The second option

Step-by-step explanation:

The given system of equation is

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The augment matrix is obtained by combining the coefficient matrix with the constant matrix to obtain;

\left[\begin{array}{cccc}1&2&0&|3\\-1&1&1&|2\\0&1&-2&|-3\end{array}\right]

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2 years ago
Which problem can be represented by the equation 12z + 2= 98
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Where are the problems?

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2 years ago
g In a survey of 500 residents, 300 were opposed to the use of the photo-cop for issuing traffic tickets.The standard error of t
Evgesh-ka [11]

Answer:

Z-score 1.96

Margin of error d= 0.04323

Step-by-step explanation:

Hello!

The study variable in this case is

X: Number of people that oppose the use of photo-cop for issuing traffic tickets in a sample of 500.

n= 500

The parameter of interest is the proportion of people that opposes it.

The estimated proportion is p'= 300/500= 0.6

To estimate the population proportion per Confidence interval you have to approximate the distribution of the sample proportion p' to normal:

p'≈N(p;p(1-p)1/n)

The mean of this distribution is p and the variance is p*(1-p)*1/n

To construct the Confidence interval, since the value of the population proportion is unknown, an estimated variance is used:

p'(1-p')*1/n ⇒ then the estimated standard error is √(p'(1-p')*1/n)

The formula for the confidence interval is:

p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

Where "Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }" represents the margin of error of the interval.

Now for a confidence level of 0.95 the value of Z is Z_{0.975}= 1.965

The estimated standard error is already calculated: \sqrt{\frac{p'(1-p')}{n} } = 0.022

The margin of error (d) is then:

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }= 1.965 * 0.022

d= 0.04323

I hope it helps!

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