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2 years ago

Which equation represents the line shown on the graph?

Mathematics

1 answer:

Mama L [17]2 years ago

8 0

Hello there,

To find out the equation you use the slope intercept form...

y = mx + b

M is the slope and b is where the line crosses the y-axis...

Now to find the slope you count the distance from two points so...

The distance from (0,2) to (1,5) is 3 units up and 1 unit over.

So the correct answer should be...

y = 3x + 2

Answer: w = 3z + 2

Hope I helped!!

-Char

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There are 200 students in the 7th grade class at Brookside Middle School. Of these students, 12% play volleyball and 15% play ba

Phoenix [80]

P(volleyball and baseball) = 4/200 x 100 = 2%
P(either volleyball or baseball) = P(volleyball ∪ baseball) = P(volleyball) + P(baseball) - P(volleyball and baseball) = 12% + 15% - 2% = 25%.

25% play either volleyball or baseball.

4 0

2 years ago

Read 2 more answers

Please answer all of them need this

VikaD [51]

First Question

For a better understanding of the solution provided here please find the first attached file which has the diagram of the the isosceles trapezoid.

We dropped perpendiculars from C and D to intersect AB at Q and P respectively.

As can be seen in $\Delta BCQ$ , we can easily find the values of CQ and BQ.

Since, $Sin(75^0)=\frac{CQ}{8}$

$\therefore CQ=8\times Sin(75^0)\approx 7.73$ ft

In a similar manner we can find BQ as:

$Cos(75^0)=\frac{BQ}{8}$

$BQ\approx2.07$ ft

All these values can be found in the diagram attached.

Thus, because of the inherent symmetry of the isosceles trapezoid, PQ can be found as:

$PQ=22-(AP+QB)=22-(2.07+2.07)=17.86$

Let us now consider $\Delta AQC$

We can apply the Pythagorean Theorem here to find the length of the diagonal AC which is the hypotenuse of $\Delta AQC$ .

$AC=\sqrt{(AQ)^2+(QC)^2}=\sqrt{(AP+PQ)^2+(QC)^2}=\sqrt{(2.07+17.86)^2+(7.73)^2}\approx21.38$ feet.

Thus, out of the given options, Option B is the closest and hence is the answer.

Second Question

For this question we can directly apply the formula for the area of a triangle using sines which is as:

Area= $\frac{1}{2}$ (First Side)(Second Side)(Sine of the angle between the two sides)

Thus, from the given data,

Area= $\frac{1}{2}\times 218.5\times 224.5\times sin(58.2^0)\approx20845$ $m^2$

Therefore, Option D is the correct option.

Third Question

For this question we will apply the Sine Rule to the $\Delta ABC$ given to us.

Thus, from the triangle we will have:

$\frac{AB}{Sin(\angle C)}=\frac{BC}{Sin(\angle A)}$

$\frac{c}{Sin(\angle C)}=\frac{a}{Sin(\angle A)}$

$\frac{17}{Sin(25^0)}=\frac{a}{Sin(45^0)}$

This gives $a$ to be:

$a\approx28.44$

Which is not close to any of the given options.

Fourth Question

Please find the second attachment for a better understanding of the solution provided her.

As can be clearly seen from the attached diagram, we can apply the Cosine Rule here to find the return distance of the plane which is CA.

$AC=\sqrt{(AB)^2+(BC)^2-2(AB)(BC)\times Cos(\angle B)}$

$\therefore AC=\sqrt{(172.20)^2+(111.64)^2-2(172.20)(111.64)\times Cos(177.29^0)}\approx283.8$ miles.

Thus, Option D is the answer.

8 0

2 years ago

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Show one way to count from $82 to $512

Sedaia [141]

First way:
The easiest and simplest way is to count by 1 starting from 82 till you reach 512.
This will go as follows:
82, 83, 84, 85, ........... , 510, 511, 512

Second way:
We can note that the two given numbers are even numbers. This means that the two numbers are divisible by 2.
Therefore, we can count by 2 starting from 82 till we reach 512.
This will go as follows:
82, 84, 86, 88, ................... , 508, 510, 512

Third way:
We can note that the units digit in both numbers is the same (the digit is 2). This means that we can count from 82 till 512 by adding 10 each time.
This will go as follows:
82, 92, 102, 112, ......................, 492, 502, 512

Hope this helps :)

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2 years ago

the number 792 and 990, written as the product of their prime factors are 792 = 23 x 32 x 11 and 990 = 2 x 9 x 5 x 1. Hence, fin

noname [10]

Answer:

198

Step-by-step explanation:

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2 years ago

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The Rotation R maps all 60° about O the center of the regular hexagon. State the image of B for the following rotation.

Andru [333]

It is B. Since each angle is 60 degrees, if you rotate B counterclockwise 6 times, it means that you rotated B 360 degrees. Therefore, the image of B would be B.

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2 years ago

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