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iVinArrow [24]
2 years ago
7

What is not a pair of equivalent fractions for 5/8 and 1/2

Mathematics
1 answer:
n200080 [17]2 years ago
7 0
Two fractions equivalent to each: Just divide or multiply both top AND bottom by the same number.<span>
5/6: 10/12 OR 15/18 
15/30: 5/10 OR 1/2 
45/60: 8/12 OR 4/6 

Rewrite each pair or fractions with common denominator: Find the difference between the two bottom numbers, and multiply top and bottom number. 

5/8 and 3/4: 4X2=8, 3X2=6. So, 5/8 and 6/8. 
2/5 and 1/2: 2/5 and 2.5/5 
9/9 and 5/7: 9/9 and ~5.7/9 

Rewrite each in simple form: Find greatest common factor and divide. 

9/54: 1/6 
20/40: 1/2 
100/110: 10/11 

Are these fractions equivalent? 
No. 5/1 and 5/5 are, because they are both 5 wholes. 1/5 is not because it is a fifth of a whole. 


In what situation can you use multiplication to find equivalent fractions? 
I'm sorry but I do not understand this question. 
</span>Source(s):<span>I hope I  helped, seeing as I have graduated with a math degree.</span>
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stich3 [128]
First, identify the ratio:
1:50 (1 foot on the model is 50 feet on the house)
to find the actual height of the window multiply 1 1/5 by 50
\frac{6}{5}*\frac{50}{1}=\frac{300}{5}
300/5 simplifies into 60
the height of the real window is 60 feet 

6 0
2 years ago
The aquarium at Sea Critters Depot contains 140 fish. Eighty of these fish are green swordtails (44 female and 36 male) and 60 a
maxonik [38]

Given that:

Total number of fish = 140

Fish are green swordtails female = 44

Fish are green swordtails male = 36

Fish are orange swordtails female = 36

Fish are orange swordtails male = 24

Solution:

A. We have to find the probability that the selected fish is a green swordtail.

\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}

\text{P(green swordtail)}=\dfrac{80}{140}

\text{P(green swordtail)}=\dfrac{4}{7}

Therefore, the probability that the selected fish is a green swordtail is \dfrac{4}{7}.

B.  We have to find the probability that the selected fish is male.

\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}

\text{P(Male fish)}=\dfrac{36+24}{140}

\text{P(Male fish)}=\dfrac{60}{140}

\text{P(Male fish)}=\dfrac{3}{7}

Therefore, the probability that the selected fish is a male, is \dfrac{3}{7}.

C. We have to find the probability that the selected fish is a male green swordtail.

\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}

\text{P(Male green swordtail)}=\dfrac{36}{140}

\text{P(Male green swordtail)}=\dfrac{9}{35}

Therefore, probability that the selected fish is a male green swordtail is \dfrac{9}{35}.

D.

We have to find the probability that the selected fish is either a male or a green swordtail.

\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}

\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}

\text{P(Male or green swordtail)}=\dfrac{96}{140}

\text{P(Male or green swordtail)}=\dfrac{24}{35}

Therefore, the probability the selected fish is either a male or a green swordtail is \dfrac{24}{35}.

4 0
2 years ago
Consider this claim: Changes in environmental conditions always result in new ecosystems and loss of biodiversity characterized
Dafna11 [192]

Answer:

If a desert became flooded, some species would immeadiately go extinct, distrupting the ecosystem, biodiversity, and the food web. This flood might cause new species to enter the ecosystem as well, through means such as rafting. Other species would be forced to adapt to the new environment, leading to adaptation and possibly speciation. For a time the ecosystem would not be very stable, but after a relatively short time, 10 or 20 years, the ecosystem could stabilize itself. So my conclusion is that ecosystems are relatively fluid, they can adapt to almost anything if they have enough time and the change in environment isn’t too drastic.

Step-by-step explanation:

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1 year ago
A. Find x. The figure is not drawn to scale.
blondinia [14]
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8x-6x = 10
2x =10
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Graphs of the following equations are straight lines except :
scoundrel [369]

Answer:

D

Step-by-step explanation:

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