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Len [333]
2 years ago
15

A graph of a quadratic function y = f(x) is shown below.

Mathematics
2 answers:
spin [16.1K]2 years ago
8 0

We are given a graph of a quadratic function y = f(x) .

We need to find the solution set of the given graph of a quadratic function .

<em>Note: Solution of a function the values of x-coordinates, where graph cut the x-axis.</em>

For the shown graph, we can see that parabola in the graph doesn't cut the x-axis at any point.

It cuts only y-axis.

Because solution of a graph is only the values of x-coordinates, where graph cut the x-axis. Therefore, there would not by any solution of the quadratic function y = f(x).

<h3>So, the correct option is 2nd option :∅.</h3>
kenny6666 [7]2 years ago
7 0

Answer:

Option B. ∅

Step-by-step explanation:

If a quadratic function f(x) is in the form of f(x) = ax²+bx+c then the solution of the function is the value of x.

If we analyze the graph for f(x) ≤ 0 solution of the function is null because parabola doesn't intercept at x axis.

Therefore there is no solution for the graphed function f(x).

Option B is the answer.

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Make y the subject of the formula x=a-2by squared
Dominik [7]

Answer:

y = ± \sqrt{\frac{a-x}{2b} }

Step-by-step explanation:

Given

x = a - 2by² ( subtract a from both sides )

x - a = - 2by² ( multiply through by - 1 to clear the leading negative )

a - x = 2by² ( divide both sides by 2b )

\frac{a-x}{2b} = y² ( take the square root of both sides )

y = ± \sqrt{\frac{a-x}{2b} }

7 0
2 years ago
The following chart shows a store?s records of coat sales over two years. 2 circle graphs. A circle graph titled 2006. Top coats
Mkey [24]

Answer:

<u>The correct answer is A. 16.5%</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly and to calculate the trend:

                   2006      2007  Trend

Top Coats    297        223       -24.92%

Parkas          210        210         + 0%  

Jackets         213        285        +33.80%

Raincoats      137        259        +89.05

Trench coats 103       127         +23.30%

Total               960     1,104        +15%

2. If the trend shown in these graphs stays constant, what percent of the market will parkas occupy in 2008?

Let's calculate the percent of the market occupied by parkas.

In 2006 = 210/960 = 21.88%

In 2007 = 210/1,104 = 19.02%

In 2008 = 210/1,270 = 16.54% (210 + 0 = 210; 1,104 + 15% = 1,270)

<u>The correct answer is A. 16.5%</u>

7 0
2 years ago
Read 2 more answers
Ian has 20 football cards, and Jason has 44 baseball cards. They agree to trade such that jason
Alina [70]

Answer:

12 trades

Step-by-step explanation:

Let's call 'x' the number of trades they will do.

After each trade, the number of cards Ian has increase by 1 (he gives 1 but receives 2), and the number of cards Jason has decrease by 1 (he receives 1 but gives 2), so after x trades, the number of cards Ian has is 20 + x, and Jason has 44 - x.

To find the number of trades when they will have the same amount of cards, we have that:

20 + x = 44 - x

2x = 24

x = 12 trades

8 0
2 years ago
What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth
uysha [10]

Answer:

The perimeter of the trapezoid is 38.25\ units

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

so

In this problem

P=QR+RS+ST+QT

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

Q(8, 8), R(14, 16), S(20, 16),T(22, 8)

step 1

Find the distance QR

Q(8, 8), R(14, 16)

substitute the values in the formula

d=\sqrt{(16-8)^{2}+(14-8)^{2}}

d=\sqrt{(8)^{2}+(6)^{2}}

d=\sqrt{100}

QR=10\ units

step 2

Find the distance RS

R(14, 16), S(20, 16)

substitute the values in the formula

d=\sqrt{(16-16)^{2}+(20-14)^{2}}

d=\sqrt{(0)^{2}+(6)^{2}}

d=\sqrt{36}

RS=6\ units

step 3

Find the distance ST

S(20, 16),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-16)^{2}+(22-20)^{2}}

d=\sqrt{(-8)^{2}+(2)^{2}}

d=\sqrt{68}

ST=8.25\ units

step 4

Find the distance QT

Q(8, 8),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-8)^{2}+(22-8)^{2}}

d=\sqrt{(0)^{2}+(14)^{2}}

d=\sqrt{196}

QT=14\ units

step 5

Find the perimeter

P=10+6+8.25+14=38.25\ units

6 0
2 years ago
Read 2 more answers
Tickets to a show cost $5.50 for adults and $4.25 for students. A family is purchasing 2 adult tickets and 3 student tickets. If
larisa [96]

Answer:

Step-by-step explanation:

The cost of an adult ticket to the show is $5.5

The cost of a student ticket to the show is $4.25

A family is purchasing 2 adult tickets and 3 student tickets. This means that the total cost of 2 adult tickets would be

2 × 5.5 = $11

It also means that the total cost of 3 student tickets would be

3 × 4.25 = $12.75

The total cost of 2 adult tickets and 3 student tickets would be

11 + 12.75 = $23.75

If the family pays $25, the exact amount of change they should receive is

25 - 23.75 = $1.25

5 0
2 years ago
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