(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:

(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:

β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:

Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:


Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.
Answer: C
Step-by-step explanation:
The answer is C
Step-by-step explanation:
C The opposite of 9 is the same distance from 0 on a number line as the absolute value of 9.
Absolute value is the distance from zero on a number line of and number positive or negative.
Bala had 9 stickers
You could set this up as a equation. Because there was a total of 26 you would for sure put =26. Next you are told Alvin has 8 MORE than Bali, therefore you would be adding the unknown value of Bala by 8. This could be represented as x+8=26. Now that you have x added to 8 you need to add another x to the equation to fully represent the problem since Alvin has 8 more stickers than Bala does. The new equation would become 2x+8=26.
You must now isolate x by first subtraction 8 from both sides which will leave you with 2x=18. Then you divide on both sides by 2 and will leave you with x=9
The equation is <span>y = -x + 2</span>