X (minutes) y (bedsheets)

Mathematics

1 answer:

pickupchik [31]1 year ago

5 0

Is that IXL? Anyway I think it’s 8 but I don’t think so anyway I tried don’t rely on me

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How much of the circle is shaded? Write your answer as a fraction in simplest form.

Alchen [17]

What I would do is find the common denominator for both fractions. The common denominator in this case would be 24 seeing as both 3 and 8 go into 24 evenly. 1/3 would equal to 8/24 by multiplying both 1 and 3 by 8 and 3/8 would equal to 9/24 by multiplying both 3 and 8 by 3. Add 8 and 9 from the fractions 8/24 and 9/24 which would give you 17/24. To find the remaining section of the circle, subtract 17 from 24 which would give you 7/24. 7/24 doesn't reduce any further so your answer would be 7/24 of the circle is shaded.

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2 years ago

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. (04.07) Luke is keeping track of the total number of hours he exercises. He started the summer having already put in 15 hours,

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X is the number of weeks he is exercising starting summer
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1 year ago

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Jeanne wants to start collecting coins and orders a coin collection starter kit. The kit comes with three coins chosen at random

lesya692 [45]

Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B), or sometimes $P_B(A)$ .

The conditional probability of event A happening, given that event B has happened, written as P(A|B) is given by
$P(A|B)= \frac{P(A \cap B)}{P(B)}$

In the question, we were told that there are three randomly selected coins which can be a nickel, a dime or a quarter.

The probability of selecting one coin is $\frac{1}{3}$

Part A:
To find the probability that all three coins are quarters if the first two envelopes Jeanne opens each contain a quarter, let the event that all three coins are quarters be A and the event that the first two envelopes Jeanne opens each contain a quarter be B.

P(A) means that the first envelope contains a quarter AND the second envelope contains a quarter AND the third envelope contains a quarter.

Thus $P(A)= \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27}$

P(B) means that the first envelope contains a quarter AND the second envelope contains a quarter

Thus $P(B)= \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}$

Therefore, $P(A|B)=\left( \frac{ \frac{1}{27} }{ \frac{1}{9} } \right)= \frac{1}{3}$

Part B:
To find the probability that all three coins are different if the first envelope Jeanne opens contains a dime, let the event that all three coins are different be C and the event that the first envelope Jeanne opens contains a dime be D.

$P(C)= \frac{3}{3} \times \frac{2}{3} \times \frac{1}{3} = \frac{6}{27} = \frac{2}{9}$

 $P(D)= \frac{1}{3}$ 

Therefore, $P(C|D)=\left( \frac{ \frac{2}{9} }{ \frac{1}{3} } \right)= \frac{2}{3}$

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2 years ago

Mai bought eleven 12-ounce bags of

ella [17]

Answer:

8.25 pounds

Step-by-step explanation:

When you multiply 12 and 11 you get 132. So then you would have to divided the total amount of ounces by 16 to get the amount of pounds

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1 year ago

You are given the sequence of digits 0625 and can insert a decimal point at the beginning at the end or at any of the other thre

malfutka [58]

Answer:

The answer is 6/25.

Hope this helps.

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2 years ago

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