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Free_Kalibri [48]
2 years ago
7

Which set of angles can form a triangle

Mathematics
1 answer:
Aleksandr [31]2 years ago
7 0

Answer:

  2 acute and 1 right

Step-by-step explanation:

The sum of angles of a triangle is always 180°.

Right angles are 90°, and obtuse angles are more than 90°. If each of the angles in the triangle is more than 0°, there obviously cannot be two angles that measure 90° or more. Just the sum of those two would be 180° or more, and that sum doesn't include the third angle.

So, any triangle can have at most one angle that is 90° or more (right or obtuse). The remaining two angles must be acute for the sum of angles to be 180°.

  2 acute and 1 right angle can form a triangle

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A positive correlation means sales are rising because of advertising
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According to the journal Chemical Engineering, an important property of a fiber is its water absorbency. A random sample of 20 p
Feliz [49]

Answer:

Step-by-step explanation:

a )

sample mean = sum total of given data / no of data

= 415.35 / 20 = 20.76

To calculate the median we arrange the data in ascending order and take the average of 10 th and 11 th term .

= 20.50 + 20.72 / 2

= 20.61

b ) To calculate the 10% trimmed mean , we neglect the largest 10% and smallest 10 % data and then calculate the mean . Here we neglect the first two smallest and last two greatest

(18.92 + 19.25 ..... + 22.43 + 22.85) / 16

= 20.74

c )

We can easily plot the data on number line from 17 to 24

d )

Maximum value of data set = 23.71 and minimum value is 18.04

mean is 20.76 , median is 20.61 and trimmed mean is 20.74

They are between maximum and minimum values of given data . Hence there is no outliers .

4 0
2 years ago
Decide whether the function is an exponential growth or exponential decay function, and find the constant percentage rate of gro
frosja888 [35]
Consider the function f ( x ) = 2479 ⋅ 0.9948x First compare this with f ( x ) po ( 1 + r ) ^ 2 We get po = 2479 And 1 + r = 0.9948 = 1 – 0.0052 r = -0.0052 < 0 Therefore, f is an exponential decay function with a decay rate of 0.0052 x 100 = 0.52% 
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A school baseball team raised $810 for new uniforms. Each player on the team sold one book of tickets. There were 10 tickets and
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Step-by-step explanation:

To find the number of tickets sold, the total revenue needs to be divided by the revenue per ticket:

  (total revenue)/(revenue/ticket) = total tickets

  $810/$3 = 270 . . . total tickets

__

None of the other numbers in the problem are needed: books per player (1), tickets per book (10).

3 0
1 year ago
se the function to show that fx(0, 0) and fy(0, 0) both exist, but that f is not differentiable at (0, 0). f(x, y) = 9x2y x4 + y
alexandr1967 [171]

Answer:

It is proved that f_x, f_y exixts at (0,0) but not differentiable there.

Step-by-step explanation:

Given function is,

f(x,y)=\frac{9x^2y}{x^4+y^2}; (x,y)\neq (0,0)

  • To show exixtance of f_x(0,0), f_y(0,0) we take,

f_x(0,0)=\lim_{h\to 0}\frac{f(h+0,k+0)-f(0,0)}{h}=\lim_{h\to 0}\frac{\frac{9h^2k}{h^4+k^2}-0}{h}\\\therefore f_x(0,0)=\lim_{h\to 0}\frac{9hk}{h^4+k^2}=\lim_{h\to 0}\frac{9k}{h^3+\frac{k^2}{h}}=0    exists.

And,

f_y(0,0)=\lim_{k\to 0}\frac{f(h,k)-f(0,0)}{k}=\lim_{k\to 0}\frac{9h^2k}{k(h^4+k^2)}=\lim_{k\to 0}\frac{9h^2}{h^4+k^2}=\frac{9}{h^2}   exists.

  • To show f(x,y) is not differentiable at the origin cheaking continuity at origin be such that,

\lim_{(x,y)\to (0,0)}\frac{9x^2y}{x^4+y^2}=\lim_{x\to 0\\ y=mx^2}\frac{9x^2y}{x^4+y^2}=\frac{9x^2\times m x^2}{x^4+m^2x^4}=\frac{9m}{1+m^2}  where m is a variable.

which depends on various values of m, therefore limit does not exists. So f(x,y) is not continuous at (0,0). Hence it is not differentiable at (0,0).

4 0
2 years ago
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