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2 years ago

Find FL if H is the circumcenter of EFG,

Mathematics

1 answer:

Zanzabum2 years ago

8 0

The artistic crop isn't helpful; it cuts off some vertex names.

The circumcenter H is the meet of the perpendicular bisectors of the sides, helpfully drawn. We have right triangle ELH, right angle L, so

EH² = HL² + EL²

EL = √(EH² - HL²) = √(5.06²-2.74²) ≈ 4.2539393507665339

Since HL is a perpendicular bisector of EF, we get congruent segments FL=EL.

Answer: 4.25

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Han made some hot chocolate by mixing 4 cups of milk with 6 tablespoons of cocoa. How many tablespoons of cocoa per cup of milk

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Answer:

Step-by-step explanation:

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2 years ago

Zane and Matt are both keen runners. Zane takes 4 minutes to jog around a running track and Matt takes 5 minutes. They start at

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2 years ago

Determine which equations below, when combined with the equation 3x-4y=2, will form a system with no solutions. Choose all that

svetoff [14.1K]

Two equations will not have solution if they are parallel and have different y-intercepts. Parallel lines have the same slope. In a slope-intercept form, the equation of the line can be expressed as,

y = mx + b

where m is slope and b is the y-intercept.

Given: 3x - 4y = 2
Slope-intercept: y = 3x/4 - 1/2

A. 2y = 1.5x - 2
Slope-intercept: y = 3x/4 - 1

B. 2y = 1.5x - 1
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C. 3x + 4y = 2
Slope-intercept: y = -3x/4 + 1/2

D. -4y + 3x = -2
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Hence, the answers to this item are A and D.

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2 years ago

Which represents a quadratic function? f(x) = −8x3 − 16x2 − 4x f (x) = three-quarters x 2 + 2x − 5 f(x) = StartFraction 4 Over x

tatyana61 [14]

Answer:

$2.\ f(x) = \frac{3}{4}x^2 + 2x - 5$

Step-by-step explanation:

Given

$f(x) = -8x^3 - 16x^2 - 4x\\f(x) = \frac{3}{4}x^2 + 2x - 5\\f(x) = \frac{4}{x^2} - \frac{2}{x} + 1\\f(x) = 0x^2 - 9x + 7$

Required

Which of the above is a quadratic function

A quadratic function has the following form;

$ax^2 +bx + c = 0 \ where \ a\neq 0$

So, to get a quadratic function from the list of given options, we simply perform a comparative test of each function with the form of a quadratic function

$1.\ f(x) = -8x^3 - 16x^2 - 4x$

This is not a quadratic function because it follows the form $f(x) = ax^3 + bx^2 + c$ and this is different from $ax^2 +bx + c = 0 \ where \ a\neq 0$

$2.\ f(x) = \frac{3}{4}x^2 + 2x - 5$

This function has an exact match with $ax^2 +bx + c = 0 \ where \ a\neq 0$

By comparison; $a = \frac{3}{4}\ b = 2\ and\ c = -5$

$3.\ f(x) = \frac{4}{x^2} - \frac{2}{x} + 1$

This is not a quadratic function because it follows the form $f(x) = \frac{a}{x^2} + \frac{b}{x} + c$ and this is different from $ax^2 +bx + c = 0 \ where \ a\neq 0$