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kherson [118]
2 years ago
14

Complete the statements for the graph of f(x) = |x|. The domain of the function is . The range of the function is . The graph is

over the interval (0, ∞). The graph is over the interval (–∞, 0).
Mathematics
2 answers:
dimaraw [331]2 years ago
7 0

Answer:

The correct answers are

1. A

2. C

3.C

4. B

Step-by-step explanation:

ioda2 years ago
5 0

Answer:

Domain of f(x): All real numbers

Range of f(x):  f(x) \geq0 ---> [0, ∞)

The graph is over the interval (0, ∞)

Step-by-step explanation:

The function absolute value of x that is written: f(x) = | x | assigns only positive values to f(x) at any value of x.

For example, if for f(x) = | x | we make

f(-23) = | -23 | then the absolute value of x "transforms" the number -23 to +23.

Then f(-23) = | -23 | = 23

This means that f(x) will be positive for any value of x.

Therefore, we can conclude that:

Domain of f(x): All real numbers

Range of f(x):  f(x) \geq0 ---> [0, ∞)

The graph is over the interval (0, ∞)

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A hospital bill is estimated to be $462.00. It ends up actually costing the patient $525.00. What is the percent error in the bi
Mamont248 [21]
In order to find the percent error, we need to first find the difference between what was expected and what is actually costed. We do this by subtracting:

525-462=63

So now we know that the expected amount was off by $63. To find the percent error, we need to take this $63, and divide it by the amount that was estimated. Let's do that now:

\frac{63}{462}=0.1364

However this is in decimal form. We need to multiply by 100 in order to get it in a percent:

0.1364*100=13.64%

Now we know that the percent error of the hospital bill estimate is 13.64%.
6 0
2 years ago
The front walkway from the street to Pam's house has an area of 250ft^2. Its length is two less than four times its width. Find
OleMash [197]

Answer: the length of the walkway is 30.64ft

The width of the walkway is 8.16ft

Step-by-step explanation:

Since the walkway has length and width, it is rectangular in shape. For a rectangle, the two lengths and two widths are equal. The area is expressed as length, L × Width,W.

The front walkway from the street to Pam's house has an area of 250ft^2. It means that

LW = 250

Its length is two less than four times its width. It means

L = 4W - 2

Substituting L = 4W - 2 into LW = 250, it becomes

W(4W - 2) = 250

4W^2 - 2W- 250 = 0

Using the general formula for quadratic equations,

W = [- b ± √b^2 - 4ac]/2a

a = 4

b = -2

c = - 250

W= [- - 2 ±√-2^2 -4(4 × -250)]/2×4

= (2 ± √4 + 4000)/8

= (2 ±63.277)/8

W= (2 + 63.277)/8 or W = (2 - 63.277)/8

W = 8.16 or W = - 7.91

Since the width cannot be negative, width = 8.16 ft

LW = 250

8.16L = 250

L = 250/8.16 = 30.64 ft

8 0
2 years ago
Read 2 more answers
A local fraternity is conducting a raffle where 55 tickets are to be sold—one per customer. There are three prizes to be awarded
harkovskaia [24]

Answer:

(a) 0.0152%

(b) 1.1663%

(c) 19.4297%

(d) 79.3787%

Step-by-step explanation:

Tickets bought by organizers = 4

Number of tickets = 55

Prizes = 3

(a) The probability that the four organizers win all of the prizes is:

P = \frac{4}{55}*\frac{3}{54}*\frac{2}{53}\\P=0.0152\%

(b) The probability that the four organizers win exactly two of the prizes is:

P = \frac{4}{55}*\frac{3}{54}*\frac{51}{53}+\frac{4}{55}*\frac{51}{54}*\frac{3}{53}+\frac{51}{55}*\frac{4}{54}*\frac{3}{53}\\P=1.1663\%

(c) The probability that the four organizers win exactly one of the prizes is:

P = \frac{4}{55}*\frac{51}{54}*\frac{50}{53}+\frac{51}{55}*\frac{4}{54}*\frac{50}{53}+\frac{51}{55}*\frac{50}{54}*\frac{4}{53}\\P=19.4397\%

(d) The probability that the four organizers win none of the prizes is:

P = \frac{51}{55}*\frac{50}{54}*\frac{49}{53}}\\P=79.3787\%

5 0
2 years ago
The lengths of a particular snake are approximately normally distributed with a given mean Mu = 15 in. and standard deviation Si
Liula [17]

Answer: 5%

Step-by-step explanation:

Let see that the snakes that are longer than 16.6 in are lomger than mean at 16.6-15=1.6 in

1.6:Sigma=1.6: 0.8=2 that means that all other snakes but longer than 16.6 in are inside +-2 Sigma. It is known that for normal distribution 95.4% of all snakes are inside +-2 Sigma

That means that 100%-95.4%=4.6% or about 5% of the snakes are longer than 16.6 in

7 0
2 years ago
Read 2 more answers
A batch of 20 semiconductor chips is inspected by choosing a sample of 3 chips. Assume 10 of the chips do not conform to custome
Hatshy [7]

Answer:

A batch of 20 semiconductor chips is inspected by choosing a sample of 3 chips. Assume 10 of the chips do not conform to customer requirements.

a) Number of different samples = 20C3 =  \frac{20!}{3!(17!)} =1140

b) 2 good and one bad chip

Number of samples = 10C2 * 10C1 = 45 * 10 =450

c) 2 good 1 bad + 1 good 2 bad + 3 bad

Number of samples = 10C2 * 10C1 + 10C1 * 10C2 + 10C3

= 450+450+120=1020

6 0
2 years ago
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