As you know that sum of complementary angles equal 90°
so,
7x + 11x = 90
18x = 90
x = 90/18
x =5
so,
option A is the correct one.
The first thing you should do for this case is to find the equation of the line that best suits the problem and then plot it.
Let X: number of months and: amount paid.
The equation of the line is
y = 15x + 25 y-intercept = 25
the slope = 15
Answer:
Georgie pays (y axis) $ 15 dollars (the spole) monthly (x-axis) in the gym with a $ 25 registration (y -intercept)
Answer:
3rd option: B(C)= 1.79C +86.03
Step-by-step explanation:
Total bill
= cost of cans(number of cans) +cost of other groceries
Let the cost of other groceries be G, and the cost of cans be X.
Given that number of cans= C,
Total bill= XC +G
If 2 cans were purchased,
2X+G= 89.61 -----(1)
If 5 cans were purchased,
5X +G= 94.98 -----(2)
(2) -(1):
(5X +G) -(2X +G)= 94.98 -89.61
5X +G -2x -G= 5.37
3X= 5.37
X= 5.37 ÷3 <em>(</em><em>÷</em><em>3</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
X= 1.79
Subst. X= 1.79 into (1):
2(1.79) +G= 89.61
3.58 +G= 89.61
G= 89.61 -3.58 <em>(</em><em>-3.58</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
G= 86.03 <em>(</em><em>simplify</em><em>)</em>
Total bill
= XC +G
= 1.79C +86.03
Thus, the function is B(C)= 1.79C +86.03.
The answer will be D. 7/10 because you have 10 numbers and you want to have a number greater than 3 so it would be 10-3=7 and 7 would go over 10 because there are 7 numbers greater than 3 but less than 10.
Answer:
a reflection over the x-axis and then a 90 degree clockwise rotation about the origin
Step-by-step explanation:
Lets suppose triangle JKL has the vertices on the points as follows:
J: (-1,0)
K: (0,0)
L: (0,1)
This gives us a triangle in the second quadrant with the 90 degrees corner on the origin. It says that this is then transformed by performing a 90 degree clockwise rotation about the origin and then a reflection over the y-axis. If we rotate it 90 degrees clockwise we end up with:
J: (0,1) , K: (0,0), L: (1,0)
Then we reflect it across the y-axis and get:
J: (0,1), K:(0,0), L: (-1,0)
Now we go through each answer and look for the one that ends up in the second quadrant;
If we do a reflection over the y-axis and then a 90 degree clockwise rotation about the origin we end up in the fourth quadrant.
If we do a reflection over the x-axis and then a 90 degree counterclockwise rotation about the origin we also end up in the fourth quadrant.
If we do a reflection over the x-axis and then a reflection over the y-axis we also end up in the fourth quadrant.
The third answer is the only one that yields a transformation which leads back to the original position.
