What’s the figure I couldn’t see anything here.
Answer:
There is a 38.97% probability that this student earned an A on the midterm.
Step-by-step explanation:
The first step is that we have to find the percentage of students who got an A on the final exam.
Suppose 13% students earned an A on the midterm. Of those students who earned an A on the midterm, 47% received an A on the final, and 11% of the students who earned lower than an A on the midterm received an A on the final.
This means that
Of the 13% of students who earned an A on the midterm, 47% received an A on the final. Also, of the 87% who did not earn an A on the midterm, 11% received an A on the final.
So, the percentage of students who got an A on the final exam is

To find the probability that this student earned an A on the final test also earned on the midterm, we divide the percentage of students who got an A on both tests by the percentage of students who got an A on the final test.
The percentage of students who got an A on both tests is:

The probability that the student also earned an A on the midterm is

There is a 38.97% probability that this student earned an A on the midterm.
Answer:
7.5 years
Step-by-step explanation:
P = $5000,
R = 4.25%,
A = $6593.75,
N =?
SI = A - P = 6593.75 - 5000 =$1593. 75

the expected value for the 3 point shot = (3 * 0.30) + (0 * 0.70) = 0.90
the expected value for the 2 point shot = (2 * 0.48) + (0 * 0.52) = 0.96
the expected value for the 2 point shot is higher than the 3 point shot so he should pass the ball
Let x = the other rational number.
x(66/7) = (48/5)
Solve for x to find your answer.