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777dan777 [17]
2 years ago
10

Ebony is cutting dough for pastries in her bakery. She needs all the pieces to be congruent triangles and has ensured that segme

nt EF ≅ segment ON and ∠MON ≅ ∠GEF. What would Ebony need to compare in order to make sure the triangles are congruent by ASA?
segment EG and segment OM
∠EFG and ∠ONM
segment NM and segment FG
∠EGF and ∠OMNEbony is cutting dough for pastries in her bakery. She needs all the pieces to be congruent triangles and has ensured that segment EF ≅ segment ON and ∠MON ≅ ∠GEF. What would Ebony need to compare in order to make sure the triangles are congruent by ASA?

segment EG and segment OM
∠EFG and ∠ONM
segment NM and segment FG
∠EGF and ∠OMN
Mathematics
1 answer:
8090 [49]2 years ago
4 0

Answer:

Ebony need to compare ∠EFG and ∠ONM

Step-by-step explanation:

we know that

If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent by ASA

In this problem

EF ≅ ON ----> the included side

To prove congruence by ASA, of triangles EFG and ONM, the corresponding angles of the included side must be congruent

The corresponding angles of the included side are

∠MON and ∠GEF

and

∠EFG and ∠CNM

so

∠MON ≅ ∠GEF  ----> given problem

and

∠EFG ≅ ∠CNM

therefore

Ebony need to compare ∠EFG and ∠ONM

Both angles must be congruent, to prove that triangles EFG and ONM are congruent by ASA

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Does the function ƒ(x) = 7x + 3 represent exponential growth, decay, or neither?
bearhunter [10]

Answer:

Neither

Step-by-step explanation:

This is a linear function as opposed to an exponential function as there are no x terms in higher powers.

4 0
1 year ago
Asap pls help and explain
eduard

Answer:

the answer would be 90

Step-by-step explanation:

100 giants fills 5/8 (100/160) of the theater leaving 3/8 of the theater for the elves.

3/8 times 240 elves is 90 elves.

If there were 150 elves that would also be 5/8 filled plus the original 5/8 filled with 100 giants! Some elves might suffer!!!

4 0
1 year ago
On an algebra test, the highest grade was 42 points higher than the lowest grade. The sum of the two grades was 138. Find the lo
miv72 [106K]


you could use this equation to help you solve it;

x + (x + 42) = 138

the first step is to combine like terms;

2x = 138 -42

2x = 96

X = 96/2

X = 48

we already solved for x now substitute it in the equation I gave you.

48 + (48 + 42) = 138

48 + 90 = 138

hope it helped...if you have any concerns just let me know:) 

3 0
2 years ago
4. Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln
pochemuha

Answer:

No these these result do not differ at 95% confidence level  

Step-by-step explanation:

From the question we are told that

  The first concentrations is  c _1= 30.0 \ g/m^3

      The second concentrations is  c _2 = 52.9 \ g/m^3

  The first sample size is  n_1 =  32

    The second sample size is  n_2 =  32

   The  first standard deviation is \sigma_1 =  30.0

     The  first standard deviation is \sigma_1 =  29.0

The mean for  Turnpike is  \= x _1 = \frac{c_1}{n}  =  \frac{31.4}{32} = 0.98125

The mean for   Tunnel is  \= x _2 = \frac{c_2}{n}  =  \frac{52.9}{32} = 1.6531

The  null hypothesis is  H_o  :  \mu _1 - \mu_2  =  0

The  alternative hypothesis is  H_a  :  \mu _1 - \mu_2  \ne  0

Generally the test statistics is mathematically represented as

              t =  \frac{\= x_1 - \= x_2}{ \sqrt{\frac{\sigma_1^2}{n_1}  +\frac{\sigma_2^2}{n_2} }}

         t =  \frac{0.98125 - 1.6531}{ \sqrt{\frac{30^2}{32}  +\frac{29^2}{32} }}

        t = - 0.0899

Generally the degree of freedom is mathematically represented as

     df =  32+ 32 - 2

     df =  62

The  significance \alpha  is  evaluated as

      \alpha  =  (C - 100 )\%

=>   \alpha  =  (95 - 100 )\%

=>   \alpha  =0.05

The  critical value  is evaluated as

      t_c  =  2  *  t_{0.05 ,  62}

From the student t- distribution table  

        t_{0.05, 62} =  1.67

So

     t_c  =  2 * 1.67

=>  t_c  = 3.34

given that

       t_c  >  t we fail to reject the null hypothesis so  this mean that the result do  not differ

       

6 0
1 year ago
Two boats depart from a port located at (–10, 0) in a coordinate system measured in kilometers, and they travel in a positive x-
stiks02 [169]
To get the points at which the two boats meet we need to find the equations that model their movement:
Boat A:
vertex form of the equation is given by:
f(x)=a(x-h)^2+k
where:
(h,k) is the vertex, thus plugging our values we shall have:
f(x)=a(x-0)^2+5
f(x)=ax^2+5
when x=-10, y=0 thus
0=100a+5
a=-1/20
thus the equation is:
f(x)=-1/20x^2+5

Boat B
slope=(4-0)/(10+10)=4/20=1/5

thus the equation is:
1/5(x-10)=y-4
y=1/5x+2

thus the points where they met will be at:
1/5x+2=-1/20x^2+5
solving for x we get:
x=-10 or x=6
when x=-10, y=0
when x=6, y=3.2
Answer is (6,3.2)
5 0
2 years ago
Read 2 more answers
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