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Grace [21]
2 years ago
11

A caterer provides a conference banquet for a price of $40 per person for 20 or fewer people but will decrease the price by $1 p

er person for everyone if there are more than 20 people. What number of people will produce the maximum revenue for the caterer?
Mathematics
1 answer:
mel-nik [20]2 years ago
7 0

Answer:

The maximum revenue is $900, obtained with 30 people

Step-by-step explanation:

Naturally, the answer should be a number equal or higher than 20, because up to 20 persons, each one pays the same. Lets define a revenue function for x greater than or equal to 20.

f(x) = x*(40-(x-20)) = -x²+60x

Note that f multiplies the number of persons by how much would they pay (here, assuming that there are more than 20).

f is quadratic with negative main coefficient and its maximum value will be reached at the vertex.

The value of the x coordinate of the vertex is -b/2a = -60/-2 = 30

for x = 30, f(x) = 30*(40-(30-20))=30*30=900

So the maximum revenue is $900.

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The lengths of the sides of triangle PQR are consecutive even integers. The perimeter of triangle PQR is 42 cm. What is the leng
Yuri [45]

Answer:

16 cm

Step-by-step explanation:

Let the three consecutive even integers representing the sides of the triangle PQR be x, (x +2) and (x + 4).

Since, perimeter of triangle PQR = 42 cm

\therefore \: x + (x + 2) + (x + 4) = 42 \\ 3x + 6 = 42 \\ 3x = 42 - 6 \\ 3x = 36 \\ x =  \frac{36}{3}  \\ x = 12 \\  \\  \because \: longest \: side = x + 4 \\  \therefore \:  longest \: side = 12 + 4 \\  \red{ \bold{ \therefore \:  longest \: side = 16 \: cm}} \\

6 0
1 year ago
Investigate the following harvesting model both qualitatively and analytically. If a constant number h of fish are harvested fro
zalisa [80]

Answer:

a. The population does not become extinct in finite time.

Step-by-step explanation:

The model for the population of the fishery is

dP/dt = P(a-bP)-h, P(0) = P_0

If we rearrange and replace the constants we have:

\frac{dP}{P(7-P)-49/4} =dt\\\\-4 (\frac{dP}{4(P-7)P+49}) =dt\\\\-4 \frac{dP}{(2P-7)^2} =dt\\\\-4 \int\frac{dP}{(2P-7)^2} =\int dt\\\\-4(-\frac{1}{2(2P-7)})=t+C\\\\\frac{2}{2P-7}=t+C\\\\ t=0 \,\,\, P(0)=P_0\\\\\frac{2}{2P_0-7}=0+C\\\\C=\frac{2}{2P_0-7}

Now we can calculate if the population become 0 in any finite time

\frac{2}{2P-7}=t+\frac{2}{2P_0-7}\\\\\frac{2}{2*0-7}=t+\frac{2}{2P_0-7}\\\\-\frac{2}{7}=t+\frac{2}{2P_0-7}\\\\

To be a finite time, t>0

t=-\frac{2}{7}-\frac{2}{2P_0-7}=0\\\\-\frac{2}{2P_0-7}=\frac{2}{7}\\\\7-2P_0=7\\\\P_0=0

We can conclude that the only finite time in which P=0 is when the initial population is 0.

Because P0 is a positive constant, we can say that the population does not become extint in finite time.

5 0
2 years ago
Each type of cable has a prescribed bend radius , which is the radius of the maximum arc into which you can loop a cable without
tiny-mole [99]
The question is asking whether it is true or false so my answer is true.
7 0
1 year ago
A right triangle has one side that measures 4 in. The angle opposite that side measures 80o. What is the length of the hypotenus
mojhsa [17]
In order to find the length of the hypotenuse, we use knowledge on trigonometric functions which would be sine and is expressed as:

sine (theta) = opposite side / hypotenuse

sine 80 = 4 / hypotenuse
Hypotenuse = 4.1 in <---- OPTION B
8 0
2 years ago
Read 2 more answers
For what values of x is x2 + 2x = 24 true?<br> –6 and –4<br> –4 and 6<br> 4 and –6<br> 6 and 4
alexgriva [62]

Answer:

Option C

x²+ 2x -24=0

x²+6x-4x-24= 0

x(x+6) -4(x+6) = 0

(x+6)(x-4) = 0

x= -6 and 4

Therefore, for x = 4 and -6 , the above given equation is true.

9 0
2 years ago
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