Answer:
Mary is
times heavier than her sister
Step-by-step explanation:
Mary's Weight = n
Sister's Weight = n - 15
To find how many times mary is heavier, we need to multiply "that many time" [let it be x] with sister's weight to get Mary's weight.
<u>e.g. </u>If someone weighs 100 and another person 50, 50 * 2 = 100, thus, 100 kg person is 2 times heaving. We do same for this:
(n - 15) * x = n
x = n/(n - 15)
3 less: -3
difference of 16p and 15p: 16p - 15p = p
is equal to: =
the difference of 3 and 1/2: 3 - 1/2 = 2.5
p - 3 = 2.5
Isolate the p. Note the equal sign. What you do to one side, you do to the other. Add 3 to both sides
p - 3 (+3) = 2.5 (+3)
p = 2.5 + 3
p = 5.5
5.5 is your answer for p
hope this helps
Answer:

Interpretation:
It means that Passenger will reach to same height after each 2/3 minutes
Step-by-step explanation:
We are given height function as

where
h is the height above the ground
t is the time
we can compare it with standard equation

Period formula is

now, we can compare and find B

we can find period


Interpretation:
It means that Passenger will reach to same height after each 2/3 minutes
Answer:
When x = 15, y= 2
When y= 10, x= 3
Step-by-step explanation:
This is a question in inverse proportion. In this proportion, an increase in one quantity would lead to a decrease in the other and vice versa.
We are to complete the table using the relationship between x and y.
Given:
y is inversely proportional to x = y ∝ 1/x
∝ = proportional to
y ∝ 1/x
y = k × 1/x
Where k = constant of proportionality
To understand the relationship between y and x, we need to find the value of k.
y = k × 1/x
From the table,
When x = 6, y = 5
5 = k × 1/6
5 = k/6
k = 6×5 = 30
y = 30 × 1/x
y = 30/x
The above relationship would enable us find the missing parts.
When x = 15, y= ?
y = 30/15
y = 2
When y= 10, x= ?
10 = 30/x
10x = 30
x = 30/10
x= 3
1) the form of the equation may be written as y = A(X - Xo)(X - X1)
Where Xo and X1 are the two roots of the equation.
2) We can fix the system of coordinates so that the vertex is in the middle of the gate => Xo = - 40 and X1 = +40
=> y = A (X + 40) (X - 40) = A (X^2 - 1600)
3) The height, at X = 0 is 25
=> A(0 - 1600) = 25
=> -1600A = 25 => A = -25 / 1600 = - 1/64
4) The equation is y = - [1/64] (X^2 - 1600)
5) You can present it in different equivalent forms.
Some of those other forms are:
1) - 64y = (x^2 - 1600)
2) x^2 = - 64y + 1600
3) X^2 = - 64 (y - 25)