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lianna [129]
2 years ago
10

Alan wants to install security cameras in his store, which has dimensions of 30 feet by 30 feet. Each camera can view an area of

approximately 112.5 ft2, with a viewing area shaped like a right triangle. How many cameras will be necessary to cover the entire store? .
If he places cameras only in the corners of the store, how much area is left uncovered?

ft2.
Mathematics
2 answers:
FinnZ [79.3K]2 years ago
8 0
30×30=900
900/112.5=8 cameras to cover

112.5×4=450
900-450=450 ft left uncovered
FinnZ [79.3K]2 years ago
6 0

Answer: There are 8 cameras will be necessary to cover the entire store.

The area is left uncovered = 450\ feet^2

Step-by-step explanation:

Given: The dimensions of store = 30 feet by 30 feet

That means store roof is in square shape, which has all its sides equal.

The area of the store roof =30\times30=900\ feet^2

The area which can be viewed by camera = 112.5\ ft^2

The number of cameras  necessary to cover the entire store

=\frac{\text{Area of store roof}}{\text{Area viewed by each camera}}=\frac{900}{112.5}=8

If he places cameras only in the corners of the store, the area is covered

=4\times112.5=450\ feet^2

Then, The area remains uncovered=900-450=450\ feet^2

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Suppose that 90% of all dialysis patients will survive for at least 5 years. In a simple random sample of 100 new dialysis patie
Keith_Richards [23]

Answer:

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Step-by-step explanation:

From the question we are told that

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     The sample size is  n  =  30

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Generally the standard deviation is mathematically represented as

      \sigma  = \sqrt{\frac{p( -p )}{n} }

=>    \sigma  = \sqrt{\frac{0.90( 1 -0.90 )}{100} }

=>    \sigma  = 0.03

Generally the he probability that the proportion surviving for at least five years will exceed 80%, rounded to 5 decimal places is mathematically represented as

       P(\^ p  >  0.80) =  P(\frac{ \^ p - p }{ \sigma }  >  \frac{0.80 - 0.90}{0.03} )

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So  

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So

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2 years ago
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<em><u>Answer:</u></em>

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2. From S to R, it's the reciprocal of the scale factor (3) so 1/3

3. From R to T, is the from a figure to a figure to a figure so we can multiply the two scale factors (2 and 3) to get 6

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4 0
2 years ago
In equilateral ∆ABC with side a, the perpendicular to side AB at point B intersects extension of median AM in point P. What is t
Sergeeva-Olga [200]

Answer:

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Step-by-step explanation:

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The diagram is given below :

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We get, ∠AMB = 90°. So, by linear pair ∠AMB + ∠PMB = 180° ⇒ ∠PMB = 90°. Also, ∠ABC = 60° and ∠ABP = 90° (given) So, ∠PBM = 30°

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Now, in ΔBMP :

sin\thinspace 30^{o}=\frac{\text{Perpendicular}}{\text{Hypotenuse}}\\\\sin\thinspace 30^{o}=\frac{\text{MB}}{\text{PB}}\\\\PB=\frac{\text{MB}}{\text{sin 30}}\\\\PB=\frac{\frac{a}{2}}{\frac{1}{2}}\implies PB = a\\\\tan\thinspace 30^{o}=\frac{\text{Perpendicular}}{\text{Base}}\\\\tan\thinspace 30^{o}=\frac{\text{MB}}{\text{PM}}\\\\PM=\frac{\text{MB}}{\text{tan 30}}\\\\PM=\frac{\frac{a}{2}}{\frac{1}{\sqrt3}}\implies PM=b= \frac{\sqrt{3}\cdot a}{2}

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3 0
1 year ago
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krek1111 [17]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
Read 2 more answers
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