Answer:
The perimeter of Δ ABC is 20 + 2
units ⇒ Last answer
Step-by-step explanation:
The perimeter of any triangle is the sum of the lengths of its three sides
The formula of distance between two points is
In Δ ABC
∵ A = (3 , 4) , B = (-5 , -2) , C = (5 , -2)
∵ AB = 10 units
∵ AC = 2
- To find its perimeter find the length of BC
∵
= -5 and
= -2
∵
= 5 and
= -2
- By using the formula above
∴ 
∴ 
∴ BC = 10 units
To find the perimeter add the lengths of the three sides
∵ P = AB + BC + AC
∴ P = 10 + 10 + 2
- Add like terms
∴ P = 20 + 2
The perimeter of Δ ABC is 20 + 2
units
<span>8x3(3x2)=24x6 = True
</span><span>4x3(6x2)=24x6 = True
</span><span>6b^3(−2b3)=−12b^6 = Ture
</span><span>3a^3(−3a^4)=−9a^7 = True
They are all correct</span>
To solve the problem, get the
percentage of each test by multiplying the score and the percentage then add it all up:
82 * .25 (highest test grade) + 65* .15 (lowest test grade) +
71*.20 (each test remaining) + 77*.20 (each test remaining) + 92*.20 (homework
grade)
= 20.5 + 9.75 + 14.2 + 15.4 + 18.4 = 78.25 or 78% in whole number
Answer:
Step-by-step explanation:
The description is too ambiguous to reconstruct the diagram. You need to post the actual diagram.
That diagram is just one way to view division by a fraction. An easier way: DIVIDING by a fraction is the same as MULTIPLYING by the upside-down fraction. For example,
(1/2) ÷ (1/4) = (1/2) × (4/1) = 2
That doesn’t help you answer this particular question, though.
Answer:
Reasonable estimation for constant of variation is 0.25 kWh per day.
Step-by-step explanation:
We are given the following information in the question:
- The graph represents the function where electricity usage.
- Electricity usage in kilowatts per hour of a clock radio varies directly with the number of days.
- The x-axis shows the number of days and usage in kilo-watt per hour is showed on the y-axis.
- Some coordinates of the graph are: (0,0), (2,0.5) and (6,1.5)
Formula for constant of variation:

Putting the values from the coordinates (2,0.5) and (6,1.5), we get:

Hence, reasonable estimation for constant of variation is 0.25 kWh per day.