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2 years ago

11

Parcel of land is sold for 163000, it appreciates at 14% compounded per year. Seller keeps it for 7 years. How much would the se

ller pay for it?

1 answer:

Simora [160]2 years ago

7 0

Answer: $434, 306.4

Step-by-step explanation:

From the question,

P= $163,000

R= 14% ; 14/100= 0.14

T=7 years

From the formula,

A= Pr e^t

A= 163000e^0.14(7)

= 163000e^0.98

= $434,306.4

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Answer:

1. Arthur is about 54 meters away from Cameron.

2. Jamie is about 56 meters away from Cameron.

3. Arthur is closer to Cameron.

Step-by-step explanation:

We have been given the locations of Cameron (70,10), Arthur (20,30) and Jamie (45,60) on the the grid in meters.

1. To find the distances of Arthur and Jamie from Cameron we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{(70-20)^{2}+(10-30)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{(50)^{2}+(-20)^{2}}$

$\text{Distance between Cameron and Arthur}=\sqrt{2500+400}$

$\text{Distance between Cameron and Arthur}=\sqrt{2900}$

$\text{Distance between Cameron and Arthur}=53.8516480713450403\approx 54$

Therefore, the distance Arthur is about 54 meters away from Cameron.

2. Let us find the distance between Cameron and Jamie.

$\text{Distance between Cameron and Jamie}=\sqrt{(70-45)^{2}+(10-60)^{2}}$

$\text{Distance between Cameron and Jamie}=\sqrt{(25)^{2}+(-50)^{2}}$

$\text{Distance between Cameron and Jamie}=\sqrt{625+2500}$

$\text{Distance between Cameron and Jamie}=\sqrt{3125}$

$\text{Distance between Cameron and Jamie}=55.9016994374947424\approx 56$

Therefore, Jamie is about 56 meters away from Cameron.

3. We can see that 56 is greater than 54, therefore, Arthur is closer to Cameron.

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