Parcel of land is sold for 163000, it appreciates at 14% compounded per year. Seller keeps it for 7 years. How much would the se
1 answer:
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Answer:
Shopper spend $3 on Apples, $4 on Grapes and $3.5 on Oranges
Step-by-step explanation:
Cost of one pound of Apple = $2x
Cost of one pound of Grapes = $(6x-5)
Cost of one pound of Oranges = $(x+2)
A shopper purchases one pound each of apples, grapes, and oranges and spends $10.50.
It can be written as:
We need to find how much the shopper spend on each fruit.
First we need to find value of x by solving equation
Solving:
The value of x is: x=1.5
Now finding cost of one pound each fruit by putting x=1.5
Cost of one pound of Apple = $2x = 2(1.5) = $3
Cost of one pound of Grapes = $(6x-5) = (6(1.5)-5)= $4
Cost of one pound of Oranges = $(x+2)=(1.5+2)=$3.5
So,
Cost of one pound of Apple = $3
Cost of one pound of Grapes = $4
Cost of one pound of Oranges = $3.5
So, shopper spend $3 on apples, $4 on Grapes and $3.5 on Oranges
Answer:
The sample size should be 273 students
Step-by-step explanation:
Here Raina wants to use 90% interval then
ME = z. SE
SE = s d/√n at end
ME/z = s d/√n
n={z.sd/ME)²
Z = 1.65 =>due to 90%confidence interval
ME= 24
sd=250
putting these value in the question we get 273 students
