Felecia's husband will catch up to her 1 hour 30 minutes after leaving.
Step-by-step explanation:
Step 1; Felecia is traveling at 45 mph, her husband starts 20 minutes after her but travels at a speed of 55 mph. So first we need to calculate how much of a head start Felecia got.
Head start =
× 45 miles an hour = 15 miles.
So Felecia got a head start of 15 miles.
Step 2; Since Felecia and her husband are traveling at different rates, we can determine how much distance there is between them. Since Felecia is traveling at 45 mph and her husband is traveling at 55 mph, their gap in between is closing at a rate of 55 - 45 = 10 miles every hour. So for every hour, the gap between them is closing by 10 miles.
Total gap initially = 15 miles.
The rate at which gap is being closed = 10 miles an hour.
Time to close the gap = 15 / 10 = 1.5 hours.
Answer:
Domain: All numbers greater than or equal to 0. By definition, the domain of a graph, is the possible x values.
Range: All real numbers. By definition, the range is all possible x values.
Not a function. A function has y value for every x value.
Answer: 60%
Step-by-step explanation: 24/40 = .6 x 100 = 60
<span> Honor roll Not on honor roll Total
Received math class requested 315 64 379
Did not get math class requested 41 80 121
Total 356 144 500
Honor roll: request granted: 315/356 = 0.88 x 100% = 88%
Not Honor roll request granted: 64/144 = 0.44 x 100% = 44%
Honor roll students were given preference in granting request than those not in the honor roll.</span>
Answer:
A)196J
B)-208J
C)3467J
Step-by-step explanation:
We are given that a 20 kg cylindrical mass is dropped onto the mat from a height of 1 m above the mat. During the impact, the cylinder’s vertical velocity reaches zero at the instant the mat has compressed to only 4 cm thick.
So, The Mat gets compressed by : 10cm - 4 cm = 6 cm=0.06 m
a)
Using Conservations of energy
Potential energy at the top = Kinetic energy at the point before touching the surface
Kinetic energy = mgh= 
b)
Work done by the mat do to stop the fall of the cylinder =
C)
Work done=

F=3467J