2x3=6x3=18 u always do PEMDAS,
Hello :
the discriminat of each quadratic equation : ax²+bx+c=0 ....(a <span>≠ 0) is :
</span><span>Δ = b² -4ac
1 ) </span>Δ > 0 the equation has two reals solutions : x = (-b±√Δ)/2a
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ <span>< 0 : no reals solutions
in this exercice : -3x²-2x+6 =0.....a = -3 b = -2 c =6
calculate : </span>Δ............................
If the adjusted ratio was 2:7, then
2x is the number of pull-ups
and
7x is the number of box jumps.
You can state that since he completed 63 box jumps at the end of his training, then
7x=63,
x=9
and
2x=18.
The total number of exercises performed is 2x+9x=18+63=81.
As at start the ratio was 5:4, then
5y was the number of pull-ups
and
4y was the number of box jumps.
Therefore, 5y+4y=81,
9y=81,
y=9
and 5y=45, 4y=36.
Answer: Initially: 45 pull-ups and 36 box jumps. At the end: 18 pull-ups and 63 box jumps.
Answer:
3.74% probability that her baby has T18
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Positive test.
Event B: The baby having T18.
T18 occurs in only 1 in 2500 pregnancies in the U.S.
This means that 
The probability of a positive test result for a baby with T18 is 0.97.
This means that 
The overall probability of a positive test result is 0.010384.
This means that 
What is the probability that her baby has T18

3.74% probability that her baby has T18