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dimaraw [331]
2 years ago
14

After allowing 20% discount on the marked price with 13%

Mathematics
1 answer:
saveliy_v [14]2 years ago
6 0

<u>Answer:</u>

The marked price of the article is 22,600

<u>Explanation: </u>

Given, selling price of an article SP = Rs. 18080

To calculate marked price MP, the formula used is  

\mathrm{SP}=\mathrm{MP}\left(1-\frac{D \%}{100}\right)

Discount D = 20%

Substituting the given values

SP = \mathrm{MP}\left(1-\frac{20}{100}\right)

18080 = \mathrm{MP}\left(1-\frac{1}{5}\right)

18080=\mathrm{MP}\left(\frac{4}{5}\right)

\mathrm{MP}=\frac{18080 \times 5}{4}

MP = Rs. 22,600

Therefore the marked price of the article is 22,600

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Organic hot dogs at the grocery store cost $2.00 each. At a major league baseball game, an organic hot dog costs $6.50. How much
ValentinkaMS [17]

325%

6.5/2 is 3.25 or

5 0
2 years ago
Ria can paint a room in 4 hours. Destiny can paint the same room in 6 hours. How long would it take Ria and Destiny to paint the
Lerok [7]

Time taken by Ria to paint a room = 4 hours

Time taken by Destiny to paint a room = 6 hours

If they work together, they complete 1 job. So,

\frac{1x}{4}+\frac{1x}{6}=1

The LCD of 4 and 6 is 12

\frac{3x+2x}{12}=1

\frac{5x}{12}=1

5x=12

x=\frac{12}{5}

Hence, both of them can paint the room in \frac{12}{5} hours or 2.4 hours.


4 0
2 years ago
Read 2 more answers
3.30 Survey response rate. Pew Research reported in 2012 that the typical response rate to their surveys is only 9%. If for a pa
Artist 52 [7]

Answer:

0% probability that at least 1,500 will agree to respond

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 15000, p = 0.09

So

\mu = E(X) = np = 15000*0.09 = 1350

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15000*0.09*0.91} = 35.05

What is the probability that at least 1,500 will agree to respond

This is 1 subtracted by the pvalue of Z when X = 1500-1 = 1499. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1499 - 1350}{35.05}

Z = 4.25

Z = 4.25 has a pvalue of 1.

1 - 1 = 0

0% probability that at least 1,500 will agree to respond

6 0
2 years ago
One month julia collected 8.4 gallons of rainwater. That month she used 5.2 gallons of rainwater to water her garden and 6.5 gal
Andru [333]

Given

One month julia collected 8.4 gallons of rainwater.

she used 5.2 gallons of rainwater to water her garden

6.5 gallons of rainwater to water flowers

Find out how much was the supply of rainwater increased or decreased by the end of the month.

To proof

As given in the question

One month julia collected 8.4 gallons of rainwater

she used 5.2 gallons of rainwater to water her garden and 6.5 gallons of rainwater to water flowers

Total water she used in the month = 5.2 gallons + 6.5gallons

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Let the supply of rainwater increased or decreased by the end of the month

be x .

Than the equation become in the form

x + 8.4 = 11.7

x = 3.3 gallons

Therefore the supply of rainwater increased or decreased by the end of the month is 3.3 gallons.

Hence proved



8 0
2 years ago
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Solve the inequality. c – 5 ≤ 6
Vilka [71]
Hello There!

Follow through:
c - 5\leq 6
Add 5 to both sides:
c - 5 + 5 ≤ 6 + 5
Simplify:
c ≤ 11

C is smaller than or equal to 11.

Hope This Helps You!
Good Luck :) 

- Hannah ❤
3 0
2 years ago
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