Answer:
P(made 2nd attempt|made 1st attempt)=P(made 2nd attempt)
Step-by-step explanation:
Here given that a basketball player that shoots 80% from the free throw line attempts two free throws.
If x is the no of shoots he makes (say) then we find that each throw is independent of the other.
In other words, because he made successful first attempt, his chances for second attempt will not change
Prob for success in each attempt remains the same as 0.80
Hence I throw is independent of II throw.
When A and B are independent,then we have
P(A/B) = P(A)
Hence answer is
P(made 2nd attempt|made 1st attempt)=P(made 2nd attempt)
1. You have the following information:
-The annual interest rate <span>is 7.2%.
- The </span><span>simple interest is calculated quarterly.
2. Then, to solve this exercise and calculate the </span><span>periodic interest rate of Marta's Account, you only have to divide the annual interest rate (7.2%) by 1/4 year. So, you have:
</span>
=(7.2%)(1/4)
=(7.2%)/4
=1.8%
<span>What is the periodic interest rate of Marta's Account?
The answer is: </span>1.8%
Answer:
At most 800 magazines the company can print daily with the remaining number of ink cartridges.
Step-by-step explanation:
We are given the following in the question:
The above inequality gives the relation for daily supply of ink cartridges where N is the number of newspaper and M is the number of magazines.
Number of newspaper to be printed daily,N = 8000
We have to find the number of magazines at most can the company print daily with the remaining number of ink cartridges.
Puting the value in the given inequality,
Thus, at most 800 magazines the company can print daily with the remaining number of ink cartridges.
Answer:
f(x + 1) = 3x² + 5x + 7
Step-by-step explanation:
To find f(x + 1), substitute x = x + 1 into f(x), that is
f(x + 1) = 3(x + 1)² - (x + 1) + 5 ← expand (x + 1)² using FOIL
= 3(x² + 2x + 1) - x - 1 + 5 ← distribute parenthesis by 3
= 3x² + 6x + 3 - x - 1 + 5 ← collect like terms
= 3x² + 5x + 7
Answer:
Which expression is equivalent to RootIndex 3 StartRoot 64 a Superscript 6 Baseline b Superscript 7 Baseline c Superscript 9 Baseline EndRoot?
2 a b c squared (RootIndex 3 StartRoot 4 a squared b cubed c EndRoot)
4 a squared b squared c cubed (RootIndex 3 StartRoot b EndRoot)
8 a cubed b cubed c Superscript 4 Baseline (RootIndex 3 StartRoot b c EndRoot)
8 a squared b squared c cubed (RootIndex 3 StartRoot b EndRoot)
