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2 years ago

11

Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ

er in the box provided or use the upload option to submit your solution. (6, 1) and (5, 4)

1 answer:

kipiarov [429]2 years ago

4 0

I think that the answer would be 5,2 but I’m not 100% sure about that. You can correct me if I need another answer

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Brainly to whoever is first and right:) - In quadrilateral ABCD, AB = BC = 1, m∠B=100°, m∠D=130°. Find BD

n200080 [17]

Answer: 1

B is the center of a circle of radius 1. A and C are on the circle 100 degrees apart. So arc AC is 100 degrees. Arc AC the long way around is 360-100=260 degrees. That means any point D on arc AC will subtend a 130 degree angle. BD is a radius for all of those, and the radius is 1.

7 0

2 years ago

9. The average diameter of an atom is 2 x 10-8 m. What if the average diameter of an atom was 1 cm? How tall would you be?

ozzi

Answer:

You'd be $2 * 10^{-6}$ times tall

Step-by-step explanation:

Given

Represent the previous and new diameter by D1 and D2;

$D_1 = 2 * 10^{-8}m$

$D_2 = 1\ cm$

To determine how tall you'd be, we need to divide D2 by D1;

$Ratio = \frac{D_2}{D_1}$

Substitute values for D2 and D1

$Ratio = \frac{2 * 10^{-8}m}{1\ cm}$

Convert cm to m

$Ratio = \frac{2 * 10^{-8}m}{1 * 0.01\ m}$

$Ratio = \frac{2 * 10^{-8}m}{0.01\ m}$

Convert denominator to exponents

$Ratio = \frac{2 * 10^{-8}m}{10^{-2}\ m}$

$Ratio = \frac{2 * 10^{-8}}{10^{-2}}$

Apply Law of indices

$Ratio = 2 * 10^{-8} * 10^2$

$Ratio = 2 * 10^{-8+2}$

$Ratio = 2 * 10^{-6}$

Hence;

<em>You'd be </em> $2 * 10^{-6}$ <em> times tall</em>

4 0

2 years ago

A baseball glove is on sale for $34.00, which is 15% off of its original price. What was the original price of the baseball glov

Y_Kistochka [10]

Answer: $40.00

Step-by-step explanation:

To find the original price, you would need to utilize the equation Original Price = Sales Price ÷ (1 - Discount). In this equation, Discount refers to the percentage of discount.

Original Price = $34.00 ÷ (1 - 0.15)

Original Price = $34.00 ÷ (0.85)

Original Price = $40.00

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2 years ago

g Steel used for water pipelines is often coated on the inside with cement mortar to prevent corrosion. In a study of the mortar

aleksandr82 [10.1K]

Answer:

$P(X$

And we can find this probability using the z table and we got:

$P(z$

Step-by-step explanation:

Let X the random variable that represent the thickness of a population, and for this case we know the distribution for X is given by:

$X \sim N(0.635,0.082)$

Where $\mu=0.635$ and $\sigma=0.032$

We are interested on this probability

$P(X$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X$

And we can find this probability using the z table and we got:

$P(z$

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2 years ago

Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

Ghella [55]

Answer: The required inequality is $x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$ and its solution is $x>8.$

Step-by-step explanation: Given that Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

Also, Heloise has written $\frac{1}{4}$ as many articles as Mustafa has and Gia has written $\frac{3}{2}$ as many articles as Mustafa has.

We are to write an inequality to determine the number of articles, m, Mustafa could have written for the school newspaper. Also, to solve the inequality.

Since m denotes the number of articles that Mustafa could have written. Then, according to the given information, we have

$x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$

And the solution of the above inequality is as follows :

$x+\dfrac{1}{4}x+\dfrac{3}{2}x>22\\\\\\\Rightarrow \dfrac{4x+x+6x}{4}>22\\\\\\\Rightarrow 11x>88\\\\\Rightarrow x>\dfrac{88}{11}\\\\\Rightarrow x>8.$

Thus, the required inequality is $x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$ and its solution is $x>8.$

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2 years ago

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