Since the troop made 10 times her then you multiply 950 by 10 and that will give you 9510
80 feet How many feet of piping is required in all? (Hint: Try dividing each radicand by 6.)
Answer:
Step-by-step explanation:
The position function is
and if we are looking for the time(s) that the ball is 10 feet above the surface of the moon, we sub in a 10 for s(t) and solve for t:
and
and factor that however you are currently factoring quadratics in class to get
t = .07 sec and t = 18.45 sec
There are 2 times that the ball passes 10 feet above the surface of the moon, once going up (.07 sec) and then again coming down (18.45 sec).
For part B, we are looking for the time that the ball lands on the surface of the moon. Set the height equal to 0 because the height of something ON the ground is 0:
and factor that to get
t = -.129 sec and t = 18.65 sec
Since time can NEVER be negative, we know that it takes 18.65 seconds after launch for the ball to land on the surface of the moon.
Answer:
Step-by-step explanation:
Let x represent the number of youth tickets purchased at the zoo.
Let y represent the number of adult tickets purchased at the zoo.
At the zoo, youth tickets cost $5 and adult tickets cost $9. A group spent a total of $90 on tickets. This means that
5x + 9y = 90
The domain of the relationship is the possible set of values of x and y that satisfies the equation. The domain of this relationship is
0 ≤ x ≤ 18
At x = 0, it means only adult tickets were purchased.
At x = 18, it means only youth tickets were purchased.
