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2 years ago

2. Let f(x) = 3x² -x+5, find f(x+1)

Mathematics

1 answer:

Anna11 [10]2 years ago

8 0

Answer:

f(x + 1) = 3x² + 5x + 7

Step-by-step explanation:

To find f(x + 1), substitute x = x + 1 into f(x), that is

f(x + 1) = 3(x + 1)² - (x + 1) + 5 ← expand (x + 1)² using FOIL

= 3(x² + 2x + 1) - x - 1 + 5 ← distribute parenthesis by 3

= 3x² + 6x + 3 - x - 1 + 5 ← collect like terms

= 3x² + 5x + 7

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Therefore the probability that at least one route is open from B to C is given by:
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(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become: $0.9984\times0.96=0.95846$

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Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:
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$0.9523+0.8-(0.9523\times0.8)=0.99$
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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard dev

Naya [18.7K]

Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 16, \sigma = 2.1$

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{20 - 16}{2.1}$

$Z = 1.905$

$Z = 1.905$ has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

Out of 180

0.0284*180 = 5.112 days

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2. Let f(x) = 3x² -x+5, find f(x+1)​

2. Let f(x) = 3x² -x+5, find f(x+1)