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ipn [44]
2 years ago
11

To construct a square, Dominic uses his straightedge to draw AB⎯⎯⎯⎯⎯ . He opens the compass to the length of AB⎯⎯⎯⎯⎯ and draws a

circle centered at point A, and then, without changing the compass opening, draws a circle centered at point B. He marks the intersections of the circles as points C and D. What should Dominic do next? Change the compass opening to the length of CA⎯⎯⎯⎯⎯ and draw a circle centered at point C and then at point D. Change the compass opening to the length of CD⎯⎯⎯⎯⎯⎯ and draw a circle centered at point C. Use a straightedge to join points C and A, C and B, D and A, and D and B. Use a straightedge to join points C and D with a line.
Mathematics
2 answers:
malfutka [58]2 years ago
5 0

Points C and D are equidistant from points A and B, so Dominic's square could be ACBD. To draw that square, his next move should be ...

... Use a straightedge to join points C and A, C and B, D and A, and D and B

Finger [1]2 years ago
3 0

Answer:

Use a straightedge to join points C and A, C and B, D and A, and D and B. Use a straightedge to join points C and D with a line.

Step-by-step explanation:

Given that Dominic uses his straightedge to draw AB⎯⎯⎯⎯⎯ .

He opens the compass to the length of AB⎯⎯⎯⎯⎯ and draws a circle centered at point A, and then, without changing the compass opening, draws a circle centered at point B.

He marks the intersections of the circles as points C and D.

Now we have AC=CB=BD=DA

Hence ACBE is a square

so next step is  Use a straightedge to join points C and A, C and B, D and A, and D and B. Use a straightedge to join points C and D with a line.

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Frank has three times as many dollars as Deandra, and Charlie has 20 more dollars than Frank. If Charlie has $65, how much money
My name is Ann [436]

Answer:

$15

Step-by-step explanation:

Let Frank be f

Deandra be d and

Charlie be c

f = 3d ......(i)

c=$20+f.....(ii)

c=$65........(iii)

Equate (ii) and (iii)

$20+f = $65

f = $45.......(iv)

Equate (i) and (iv)

3d = $45

d = $15

Deandra has $15.

8 0
2 years ago
Read 2 more answers
Jerome solved the equation below by graphing. log Subscript 2 Baseline x + log Subscript 2 Baseline (x minus 2) = 3 Which of the
Alina [70]

Answer:

Step-by-step explanation:

This question is too difficult

5 0
2 years ago
Read 2 more answers
If the foreign exchange rate between the japanese yen and the euro is 190:1, how many yen will equal 10 euros?
alexgriva [62]

Alright, lets get started.

The foreign exchange rate between the japanese yen and the euro is 190:1 given.

It means 1 euro = 190 yen

We are asked to find how many yen will be equal to 10 euros.

Means we need to multiply given euros with 190 because 1 euro = 190 yen

Hence 10 euros = 190 * 10 yen

10 euros = 1900 yen : Answer

Hope it will help :)

4 0
2 years ago
Hi. Please I need help with this :
ki77a [65]

Answer:

1.79553

Step-by-step explanation:

Step 1: Write expression

log₁₀(√(69.5² - 30.5²))

Step 2: Evaluate square root

log(√(4830.25 - 930.25))

log(√3900)

log(62.45)

Step 3: Find log

log₁₀ (or log)

log(62.45) = 1.79553

-------------------------------------

To use the table method. we find values that are easily evaluated by log₁₀

log₁₀(10) = 1

log₁₀(50) = 1.69897

log₁₀(100) = 2

So we know that log₁₀(62.45) is between 1 and 2 and greater that 1.69897.

3 0
2 years ago
Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant
pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)

Applying the following property of exponentials numbers in (II):

e^{a}.e^{b}=e^{a+b}

Therefore e^{-28k} can be written as e^{-14k}.e^{-14k}

152=190-Ae^{-14k}.e^{14k}

Replacing (I) in the previous equation:

152=190-76e^{-14k}

Solving for k:

Subtracting 190 both sides, dividing by -76:

0.5=e^{-14k}

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

Ae^{-14(-Ln(0.5)/14)}=76\\Ae^{Ln(0.5)} =76\\A(0.5)=76

Dividing by 0.5

A=152

7 0
2 years ago
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